Is 0.5sin2x the Fourier Series of sinx*cosx?

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The Fourier series of sin(x)cos(x) is indeed 0.5sin(2x), as confirmed by a trigonometric identity. This identity demonstrates that sin(x)cos(x) simplifies directly to 0.5sin(2x). There are no additional terms in the series because the uniqueness of Fourier series dictates that all other coefficients must be zero. Therefore, the assertion that the Fourier series consists solely of 0.5sin(2x) is correct. Understanding this relationship clarifies the nature of Fourier series in this context.
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My professor said the Fourier series of sinx*cosx is simply 0.5sin2x.

Is this right?? Is there no summation??

I don't understand why .. Help!
 
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She's right, by uniqueness of Fourier series.

Trig identity for sin2x shows that sin x*cos x=0.5sin2x.

This is the form of a Fourier series, hence the unique. (All the other infinitely many terms are 0.)
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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