- #1
fargoth
- 320
- 6
I've see this neat proof:
http://www.youtube.com/watch?v=E-d9...eature=iv&annotation_id=annotation_3085392237 (for some reason the youtube tag didn't work in preview...)
And now I don't see how what I've learned about series convergence is true...
I've been told that if [itex]a_n > b_n \forall n[/itex] then [itex] \sum a_n > \sum b_n [/itex] therefore, if [itex] \sum b_n [/itex] is divergent then, [itex] \sum a_n [/itex] must be too.
Also, If the partial sum diverges, the series is said to be divergent, isn't it?
And what about [itex] a_n \neq 0 [/itex] for n that tends to infinity?
So many ways I could show this series diverges, yet he show it's equal to -1/12?
Where am I, or is he, wrong?
http://www.youtube.com/watch?v=E-d9...eature=iv&annotation_id=annotation_3085392237 (for some reason the youtube tag didn't work in preview...)
And now I don't see how what I've learned about series convergence is true...
I've been told that if [itex]a_n > b_n \forall n[/itex] then [itex] \sum a_n > \sum b_n [/itex] therefore, if [itex] \sum b_n [/itex] is divergent then, [itex] \sum a_n [/itex] must be too.
Also, If the partial sum diverges, the series is said to be divergent, isn't it?
And what about [itex] a_n \neq 0 [/itex] for n that tends to infinity?
So many ways I could show this series diverges, yet he show it's equal to -1/12?
Where am I, or is he, wrong?
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