Is a Metric Space with Infinite Distance Totally Bounded?

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It seems strange, but would a metric space consisting of two points, X={a,∞} be totally bounded, but not bounded? because d(a,∞)=∞. But for all ε>0, X=B(ε,a)UB(ε,∞).

It's been proven that totally bounded→bounded, so this is wrong. Why?
 
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johnqwertyful said:
So if we assume that the distance between every two points is finite

This "assumption" is incorporated into the definition of metrics.
 
the axioms for a metric space state that for any two points in the metric space, their distance is a real (and finite) number.
 
A sphere as topological manifold can be defined by gluing together the boundary of two disk. Basically one starts assigning each disk the subspace topology from ##\mathbb R^2## and then taking the quotient topology obtained by gluing their boundaries. Starting from the above definition of 2-sphere as topological manifold, shows that it is homeomorphic to the "embedded" sphere understood as subset of ##\mathbb R^3## in the subspace topology.
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