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DaveC426913
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A definition was put forth (https://www.physicsforums.com/showpost.php?p=1091947&postcount=19") that "A thing is black if it absorbs all the visible radiation incident upon it". This is a needless condition - whether the object absorbs anything is irrelevant. The only requirement for an object to be black is that no photons are coming from the object. (eg. In a dark room, the object absorbs no photons.)
Nonetheless, if "no emissions" is technically unacceptable, then can we come up with a term that means "no photons leave the object"?
I think you're bifurcating bunnies here. Correct me of I'm wrong but, without worrying about the details, an object reflects photons by absorbing them and re-emitting them. We don't call this emission, but technically it is.Gokul43201 said:A perfect reflector has an emissivity of zero (from energy conservation and Kirchoff's Law). So, if it emits no light...
Nonetheless, if "no emissions" is technically unacceptable, then can we come up with a term that means "no photons leave the object"?
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