Is Faster-Than-Light Travel Possible Relative to Other Celestial Bodies?

[eekf]

In the reference frame of the apparatus they have traveled at 90 deg with respect to each other. Your apparent contradictions arise from constantly mixing up reference frames.

Sorry if this confuses you. I am trying to use sound to evaluate the calculations made by MM (provided the assumptions they claim to have made). I am trying my best to keep reference frames apart. As I said before: I am not trying anything new. I am not trying to start a new theory.

I am claiming that the interference screen will always measure the same frequency for both signals. And you have already explained very well why: The source, the receiver and all reflecting elements are at rest to each other.

etc..

I agree they will measure the same frequency, as they get combined to the same direction again (using the mirrors). However, in the MM experiment, you are effectively using the wavelengths of the light to measure the difference in path lengths the light is travelling. As such the wavelength in the "absolute" reference frame in the various arms are crucial.

 

[eekf]

I am claiming that the interference screen will always measure the same frequency for both signals. And you have already explained very well why: The source, the receiver and all reflecting elements are at rest to each other.

Even if the reflecting elements are stationary to the source and receiver (which I did not imply), unless sound is traveling ballistically, it will not hit the reflecting element (using the MM assumptions). Unless the sound wave is directed to have the same v component (wrt medium) as the source reflector and receiver (i.e. not 90 degrees), it will not hit the reflector, unless the reflector is behind me.

 

[A.T.]

In the reference frame of the apparatus they have traveled at 90 deg with respect to each other. Your apparent contradictions arise from constantly mixing up reference frames.

Sorry if this confuses you.

You are rather confusing yourself here.

However, in the MM experiment, you are effectively using the wavelengths of the light to measure the difference in path lengths the light is travelling.

The actual path lengths are not the point here. The arms don't have exactly the same length anyway. What you measure by the phase shift is the time delay of arrival between the signals. If that changes, the waves would propagate at different speed depending on their direction in the frame of the instrument. Light waves never do this. Sound waves do, if the instrument moves in the medium.

As such the wavelengths in the "absolute" reference frame in the various arms are crucial.

No they are not. The wavelengths in the arms don't affect the time the signal needs to travel both ways in an arm. And only this time shift determines the phase shift in the interference wave, after reunion.

Even if the reflecting elements are stationary to the source and receiver (which I did not imply), unless sound is traveling ballistically, it will not hit the reflecting element (using the MM assumptions). Unless the sound wave is directed to have the same v component (wrt medium) as the source reflector and receiver (i.e. not 90 degrees), it will not hit the reflector, unless the reflector is behind me.

Well I have already addressed this:

This is true if you use a sonic-laser (focused sound beam). And this behavior is very different from a light-laser, which always hits the mirror and comes back to you, regardless how you and the mirror (at rest to each other) are moving relative to anything. Do you now understand the difference between light and sound?

 

[eekf]

The actual path lengths are not the point here. The arms don't have exactly the same length anyway. What you measure by the phase shift is the time delay of arrival between the signals.
etc..

As far as I understand the experiment tried to measure the changes in the path length differences as the table is rotated using a constant light signal (no instantaneous pulses). Nobody ever claimed the arms have to be the same length.

However their differences give an interference pattern. As the table is rotated, it was postulated that the interference pattern has to change given an ether velocity relative to the system as the light path lengths (in the absolute frame) change, due to the movement of the system through it. We all know they did not change.

The calculations did not take into consideration the angle between the light paths or the Doppler effect.

If the difference in number of waves in the different arms (in an absolute reference frame) stays the same regardless of the velocity v for any mathematical model, it would predict a null result, i.e. no change in interference.

If I am mistaken in the original experiment and its setup, please point me to alternative original documents.

If I am mistaken in my understanding that no fringe shifts in interference pattern indicates the number of waves in the arms (and the phases between the two waves when "recombined") stay constant, please correct me.

As far as I understand, if they do not stay the same (in all reference frames, regardless of mathematical model you use) you will have fringe shifts, which does NOT correspond with the actual measured result. A valid model therefore per definition MUST predict the difference between the number of waves in the arms to be constant for all v. If I am wrong on this, please point me to some documentation on interference patterns, because I obviously do not understand it.

 

[vin300]

I agree, but if I am not there anymore because I am moving with respect to the water, it will come back behind me. This does not have to do with reflection, but with the fact that I am moving with respect to the water which propagates the wave at a fixed speed (not related to my velocity).
Therefore for it to reach me (when I am moving), I have to send it at a different angle.

http://en.wikipedia.org/wiki/File:Time-dilation-002.svg
In the image, light is sent out at 90 deg, but from the perspective of an observer through the normal to the plane, the wave goes diagonal, because the velocity of the moving observer adds vectoriallyto perpendicular velocity as seen by the traveling observer.
The latter still sees every point on the diagonal lines move perpendicular to his motion.
The same happens with sound, that is why it doesn't come behind you.
There is no distinction between reflection of light and that of sound, objecting to A.T.'s cloudy point

 

[vin300]

Wy isn't the image visible?
http://en.wikipedia.org/wiki/File:Time-dilation-002.svg"

 

[vin300]

Anyway, there are practical problems with doing MM with sound .A sound splitter which allows vibration in two directions only is to be used which becomes a thoght. Doing it underwater while in motion is something this forum doesn't allow to write(a foul word)
If it is somehow possible, then you hear beats(or not, depending on the difference in frequencies, it gives beats or diff tones)

 

[A.T.]

There is no distinction between reflection of light and that of sound, objecting to A.T.'s cloudy point

It is not about the difference in reflection of light and sound. It is about how to aim a theoretical sonic-laser to hit a reflector at rest in your frame and at 90° to your movement trough the sound's medium. Unlike with light you cannot just aim it at the reflector, because the beam will stay behind with the medium and miss the reflector. This was correctly stated by eekf but he still fails to see the difference between light and sound here.

 

[GoodPR]

Eekf, to say that anything your letting off at 90 would not come back to you does not apply to light as it does in water. In water you can travel (theoritcally) faster than the sound through the water, however you can not move faster than light, so therefore it could reflect back to you from 90, eventually (if your talking about a stationary reflection point)

As for this huge argument your having over the time it will take light to get from between the two mirrors. Relative velocity will not change any measurements you take inside the ship.
If it changed it would mean that when you looked to the back of your ship it would seem long. Since the whole ship is traveling the same speed, there would be no apparent effect on either the time it takes the light to travel, or doppler effect, similar to the boats traveling the same speed. Instead being inside the ship you see the rest of the universe as being stretched and doppler shifted.

Although, in regards to how Eekf originally talked about light seeming to travel + or - your velocity +c I understand what he is getting at, despite that we always know we observe light to be c regardless of velocity.


Also note in your example of the two boats, that in order for them to not notice a doppler shift between each other, they have to be traveling with the same velocity and traveling parallel to each other.

 

[eekf]

http://en.wikipedia.org/wiki/File:Time-dilation-002.svg
In the image, light is sent out at 90 deg, but from the perspective of an observer through the normal to the plane, the wave goes diagonal, because the velocity of the moving observer adds vectoriallyto perpendicular velocity as seen by the traveling observer.
The latter still sees every point on the diagonal lines move perpendicular to his motion.
The same happens with sound, that is why it doesn't come behind you.
There is no distinction between reflection of light and that of sound, objecting to A.T.'s cloudy point

My apologies vin300. I read up on it again last night, and you are right. I think Bradley showed this in the 18th century allready. The direction of the wavefront (in the water) will be at an angle related to v/c because of multiple consecutive waves forming a wavefront. I therefore do not have to aim in front of me.

I think the wave will still have a Doppler shift though.

 

[eekf]

Also note in your example of the two boats, that in order for them to not notice a doppler shift between each other, they have to be traveling with the same velocity and traveling parallel to each other.

Same velocity. Direction of travel is inherent in velocity, as it is a vector. Speed is something different though.

 

[eekf]

As for this huge argument your having over the time it will take light to get from between the two mirrors. Relative velocity will not change any measurements you take inside the ship.

Actually I think we have allready covered that earlier. If you change your velocity, unless you re-synchronise your clocks, you will have incorrect (improper) time measurements. Not elapsed time measurements at any point, but the synchronisation of your clocks at different positions in the ship will be out. You have to accept this as it is part and parcel of SRT.

It will therefore be impossible inside the ship to tell what happened first by reading the clocks, unless you re-synchronise.

Typically people will not pitch up for meetings at the right time :}

 

[eekf]

Anyway, there are practical problems with doing MM with sound .A sound splitter which allows vibration in two directions only is to be used which becomes a thoght. Doing it underwater while in motion is something this forum doesn't allow to write(a foul word)
If it is somehow possible, then you hear beats(or not, depending on the difference in frequencies, it gives beats or diff tones)

I agree it would be very difficult or impossible. I do not expect a frequency shift. If a non-null result can be found (which please I have only now actually started doing the calculations taking Doppler into account) you will only get a beat whilst you rotate the table.

I have actually stated that I want use calculations for a MM sound experiment to evaluate the MM predictions as for the effects taken into account in their predictions provided the assumptions they made.

Currently I have found that just looking at the speed of light and the movement of the platform through a stationary environment is not enough, as the experiment actually measures the light path lengths according to wavelengths. You therefore have to take Doppler effects into account.

It may turn out that taking Doppler into account actually predicts a bigger result.

 

[A.T.]

as the experiment actually measures the light path lengths according to wavelengths.

No it doesn't. How would you do that? Multiply the number of waves with wavelength? You have no idea how many waves there are in the arms, because you don't know the exact arm lengths anyway. And the number of waves doesn't matter. All that matters is if the signal-run-time difference between the arms (and therefore the phase shift) changes, when you change the orientation of the arms.

You therefore have to take Doppler effects into account.

No

 

[GoodPR]

Same velocity. Direction of travel is inherent in velocity, as it is a vector. Speed is something different though.

I disagree, If you are traveling towards a boat that is also traveling towards you, light would blue shift, your boats would hit the waves faster and thus increasing their frequency in much the same way. If you were traveling directly away from each other waves would take longer to travel to you and would have a reduced frequency. Any relative direction between those and it will be some mix of the two, with 90 being unchanged, you have to travel parallel, but not necessarily beside each other.

Actually I think we have allready covered that earlier. If you change your velocity, unless you re-synchronise your clocks, you will have incorrect (improper) time measurements. Not elapsed time measurements at any point, but the synchronisation of your clocks at different positions in the ship will be out. You have to accept this as it is part and parcel of SRT.

There must be something I'm missing here, why would your clocks ever become un synchronized? Did your entire ship not accelerate at the same speed?

 

[vin300]

To do theMM with sound, use two sources of same freq in the two dir with tubes