- #1
shamieh
- 539
- 0
Evaluate the Integral.
Just need someone to check my work.
\(\displaystyle
\int sec^4y \, tan^4y\)
\(\displaystyle \tan^4y * sec^2y * sec^2y \, dx\)
\(\displaystyle tan^4y * (1 + tan^2y) * sec^2y\)
\(\displaystyle u = tany\)
\(\displaystyle du = sec^2y\)
\(\displaystyle \int u^4 * (1 + u^2) * du\)
\(\displaystyle \int u^4 + u^6 * du\)
\(\displaystyle \frac{u^5}{5} + \frac{u^7}{7} + C\)
\(\displaystyle \frac{tan^5x}{5} + \frac{tan^7x}{7} + C\)
Just need someone to check my work.
\(\displaystyle
\int sec^4y \, tan^4y\)
\(\displaystyle \tan^4y * sec^2y * sec^2y \, dx\)
\(\displaystyle tan^4y * (1 + tan^2y) * sec^2y\)
\(\displaystyle u = tany\)
\(\displaystyle du = sec^2y\)
\(\displaystyle \int u^4 * (1 + u^2) * du\)
\(\displaystyle \int u^4 + u^6 * du\)
\(\displaystyle \frac{u^5}{5} + \frac{u^7}{7} + C\)
\(\displaystyle \frac{tan^5x}{5} + \frac{tan^7x}{7} + C\)