Is the Electric Field Inside an Irregular Shaped Conductor Always Zero?

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In an irregular shaped charged conductor, the electric field inside is always zero in a static situation, as the charges redistribute themselves to cancel any internal electric field. This occurs because, without an external electric field, the net charge at each point within the conductor remains zero, despite local charge displacement. When external fields are present, the charges move to the surface, ensuring that the internal electric field remains null. The distribution of surface charges is specifically arranged to prevent any electric field from penetrating the conductor. This principle holds true only in static conditions.
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In an irregular shaped charged conductor will the electric field E at all points within the conductor be zero? If yes, then how?
 
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I assume you are talking about a purely static situation.
Without external electric field, the net electric charge in each point of the conductor is zero (lets keep it simple: I assume there are no excess charges in the conductor).
Under the action of an external field, the positive and negative charges in the conductor displaces, so that the net electric charge in each point of the conductor (local charge) is not zero. If you sum the charge of all these points over the whole volume (global charge), it will however remains equal to zero.
The local charges are so smart that they arrange themselves so that the field is zero in the whole conductor. It is however a very difficult task to compute the local distribution for complex geometries.
 
Thanks for the reply. But if a conductor is charged, the charges are spread on its surface. Will not those charges impose an electric field within the conductor? Will the local charges again arrange themselves to cancel the field produced?
 
The trick is that the charges are distributed over the surface precisely such that there is no electric field inside the conductor. This is only true for the static case!
 
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