- #36
Aquamarine
- 160
- 4
You did not answer my questions.Hurkyl said:I am saying that anything that can be modeled by differentiable manifolds can be modeled equally well in Euclidean space.
This fact comes about because every n-dimensional differentiable manifold is homeomorphic to an n-dimensional surface in some higher dimensional Euclidean space.
Informally speaking, this means any statement about a differentiable manifold is true if and only if it is also true about the corresponding surface in Euclidean space.
Furthermore, if the manifold is Riemann, the surface can be chosen so the Riemann metric coincides with the Euclidean metric. For pseudo-Riemann manifolds, I think there's a corresponding theorem for Minowski space (which is just Euclidean space with a different dot product)