Is the inner product a bilinear function in vector spaces?

quasar_4
Messages
273
Reaction score
0
Hello all,

I have two questions that are fairly general, but slightly hazy to me still. o:)

1) Can we consider the inner product to be a bilinear function, or not? I would like to think of it as a mapping from an ordered pair of vectors of some vector space V (i.e. VxV) to the field (F), and I know by definition the inner product is conjugate linear as a function of it's first entry (or second, depending on which text you use). But isn't the inner product also linear as a function of either entry whenever the other is held fixed, making it bilinear?

2) Can every mapping from a finite dimensional vector space V to it's field be considered an inner product of something? What about the infinite dimensional case?
 
Physics news on Phys.org
1) Yes, obviously: what is a bilinear map?

2) No, equally obviously. If you allow mapping to mean linear functional then you need the Reitz representation theorem. But since very few vector spaces have inner products the answer is still 'NO', for equally obvious reasons.
 
Thread 'Derivation of equations of stress tensor transformation'
Hello ! I derived equations of stress tensor 2D transformation. Some details: I have plane ABCD in two cases (see top on the pic) and I know tensor components for case 1 only. Only plane ABCD rotate in two cases (top of the picture) but not coordinate system. Coordinate system rotates only on the bottom of picture. I want to obtain expression that connects tensor for case 1 and tensor for case 2. My attempt: Are these equations correct? Is there more easier expression for stress tensor...

Similar threads

Back
Top