Is the Molar Concentration of K+ in K2S2O4 Double That of S2O4^2-?

Thread starter Andrax
Start date Oct 26, 2013

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The discussion centers around the molar concentration of a solution containing the ions (2k+ and (S2O4)2-), specifically questioning whether the concentration of 2k+ is equal to 1 mol/L or 2 mol/L. It is established that the concentration of (S2O4)2- is 1 mol/L, leading to confusion about the concentration of 2k+. The key point clarified is that since there are two potassium ions (k+) for each formula unit of (S2O4)2-, the concentration of 2k+ is indeed 2 mol/L, not 1 mol/L. This highlights the importance of understanding stoichiometry in solutions.

Oct 26, 2013

Andrax

suppose that the molar concentration of (2k+ , (S2O4)2-) is C=1mol/l

we have C((S2O4)2-)=C=1mol.l but does C(2k+)=1 mol/l ? or 2C=2mol/l(since there are 2 k+ )

this question might be silly , but this really confused me and i can't come up with the correct answer

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Oct 26, 2013

Borek

Mentor

2 mol/L.

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