Is the Potential V=x^2-y^2+z^2 Valid in Free Space?

AI Thread Summary
The potential distribution equation V = x² - y² + z² does not hold in free space, as it fails to satisfy Laplace's equation. Poisson's equation indicates that the Laplacian of the potential relates to charge density, but since the given potential is dimensionally incorrect, any derived charge density is also invalid. The Laplacian of the potential yields a constant value of 2, suggesting a charge density of 2*epsilon, but this is based on an incorrect potential. Therefore, the potential cannot be used to accurately determine charge density. The discussion concludes that the initial potential equation is fundamentally flawed.
knavneet
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Can anyone tell me if the potential distribution equations V= x2-Y2+Z2
holds in free space, if not, please help me to find the charge density from the given potential .
 
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Hint:What does Poisson's Equation tell you?
 
Del2V=2 for the given V, so the given potential doesn't satisfy Laplace equation, So i think this potential is not possible in free space. But how to calculate charge density then?
 
Yes, Laplace's equation is not valid. However Poisson's equation is. As gabbagabbahey said, What does Poisson's equation tell you?
 
According to Poisson equation Del2V=-charge density / epslion ,
But in our problem Del2V=2 , So charge density = 2*epsilon , Is it the answer now ?
 
On the basis of what you have said, no. The equation, V= x2-y2+z2 is dimensionally incorrect. Therefore any answer derived from it cannot be correct.
 
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