Is the Wave Equation at Infinity Always Zero?

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The wave equation at infinity is stated to be zero, leading to the question of whether the square of the wavefunction, |ψ(x,t)|², is also zero at infinity. It is clarified that while the wavefunction itself approaches zero, the interpretation of |ψ(x,t)|² relates to the probability of finding a particle at specific points. The discussion emphasizes that the probability of finding a particle exactly at plus or minus infinity is indeed zero, as 0 squared equals zero. Thus, the conclusion is that the square of the wavefunction at infinity is also zero. This highlights the relationship between the wavefunction and its probabilistic interpretation in quantum mechanics.
Niles
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Homework Statement


Hi all.

The wave equation at plus/minus infinity is zero:

\left. {\left| {\psi (x,t)} \right| } \right|_{ - \infty }^\infty= 0

Does this also mean that:

<br /> \left. {\left| {\psi (x,t)} \right|^2} \right|_{ - \infty }^\infty=0 <br />
?
 
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no.

An interpretation of the square of the wavefunction is the probability of finding it somewhere; i.e.\int^{a}_{b}|\Psi(x,t)|^{2}dx is the probability of finding the particle between a and b. you're looking at the probability of finding the particle inbetween +/-\infty. I.e. anywhere.
 
I'm not talking about the integral, but only the square of the norm of it. So I am only looking at the probability of finding the particle at exactly + and - infinity.

Will this equal zero?
 
oh, yeah. 0 squared is zero.
 

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