Is there a local interpretation of Reeh-Schlieder theorem?

In summary, Non-philosophically inclined experts in relativistic QFT often insist that QFT is a local theory and are not convinced by philosophical arguments for non-locality. However, the Reeh-Schlieder theorem, which is based on the Wightman axioms, suggests that acting with a local operator can create an arbitrary state in a different location. This theorem is a result of quantum entanglement and does not contain any philosophical concepts, making it purely mathematical physics. Some experts argue that this does not demonstrate physical non-locality since the operators involved are not physically realizable. However, others argue that the mathematical formulation of QFT itself is non-local.
  • #71
Demystifier said:
What Bell has shown is that quantum nonlocality is not like this classical non-spooky "nonlocality".
I'd more put it that Bell has shown that one or more of his assumptions about what happens when we perform a measurement and describe it classically are not satisfied in an experiment that violates a Bell inequality. Bell's assumptions about what a random field looks like are too strong. We can be on the same page if you have a look at this, perhaps,
upload_2018-4-13_10-28-3.png

arXiv:cond-mat/0403692, however my more recent papers on random fields have moved the discussion somewhat and put much more mathematical backbone into the relationship between quantum and random fields.
 

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  • #72
A. Neumaier said:
But relativistic QFT has eliminated again the action at a distance.

That does not seem to be the case by your own account(both of them, I will explain). Since you deny the physicality of "virtual particles" then we are left with just a mathematical relation hinting at nonlocality. If you say that these are real photons(as I gathered from your interpretation FAQ), then assume two particle world, then how did the particles know about each other AND their distance from each other (to send to each other the appropriate photon/s to represent their momentum that results ) unless their presence inherently detected by each other nonlocally. It seems that the particles interaction is via an effect that is due to the particles presence, hence, nonlocality.

This question is also to other posters.
 
  • #73
Demystifier said:
Are you saying that relativistic QFT cannot explain the experiments that show violation of Bell inequalities?
No. I was saying what I wrote. To get from QFT the setting in which Bell experiments are performed requires already several approximations
 
  • #74
martinbn said:
Quantum mechanics has no action at a distance (but I agree with Einstein that it is spooky).
?

Interacting nonrelativistic 2-particle quantum systems are defined by an action principle and have obvious action at a distance.
 
  • #75
Demystifier said:
Those correlations can be explained by local deterministic beables. The Bell-type correlations cannot. That's why the latter are much spookier.
But Einstein didn't know Bell's theorem, and hence couldn't have referred to this kind of spookiness.
 
  • #76
ftr said:
That does not seem to be the case by your own account
Nonsense.

Bell nonlocality is only correlation at a distance and has nothing to do with action at a distance.

Photons transmitted in optical fibers (as used for long-distance Bell experiments) have nothing to do with virtual particles. They are effective quasiparticles moving not with the vacuum speed of light (as the QFT photons) but at lower speed.
 
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  • #77
A. Neumaier said:
Nonsense.

I really meant the coulomb potential as modeled in QFT as in ZEE's. but now I am also confused by your declaration "Any potential acts at spooky distance!".
 
  • #78
ftr said:
now I am also confused by your declaration "Any potential acts at spooky distance!".
Two interacting (classical or quantum) particles correspond to a dynamics where the first particle at x immediately responds to the second far away particle at y by the force obtained as the gradient of the potential V(x-y). This is an action at a distance in Newton's sense (and can be cast in terms of the variation of a nonlocal action in Lagrange's sense). Thus it is spooky in Einstein's sense.
ftr said:
the coulomb potential as modeled in QFT as in ZEE
Well, this leads to fully local QED; the apparent nonlocality is an artifact of the gauge in which the theory is written.

Of course one can write any local theory in nonlocal terms, but this does not make it nonlocal, or change the fact that everything observable is local in the sense of extended causality.
 
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  • #79
A. Neumaier said:
Two interacting (classical or quantum) particles correspond to a dynamics where the first particle at x immediately responds to the second far away particle at y by the force obtained as the gradient of the potential V(x-y). This is an action at a distance in Newton's sense (and can be cast in terms of the variation of a nonlocal action in Lagrange's sense). Thus it is spooky in Einstein's sense.

Well, this leads to fully local QED; the apparent nonlocality is an artifact of the gauge in which the theory is written.

Of course one can write any local theory in nonlocal terms, but this does not make it nonlocal, or change the fact that everything observable is local in the sense of extended causality.

That is why one should always use retarded potential and fields. Which is something neglected at full quantum level and also at semiclassical one (the H atom in the 1928 Dirac theory).
 
  • #80
dextercioby said:
That is why one should always use retarded potential and fields. Which is something neglected at full quantum level and also at semiclassical one (the H atom in the 1928 Dirac theory).
Do you really mean that one should never use the Feynman propagator?
 
  • #81
Demystifier said:
Anything published in a physics journal is - physics. :wink:
Hm, that's a pretty uncritical view about publications!:cry:
 
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  • #82
dextercioby said:
That is why one should always use retarded potential and fields. Which is something neglected at full quantum level and also at semiclassical one (the H atom in the 1928 Dirac theory).
You have to carefully keep in mind what you like to calculate to decide which of the infinitely many Green's functions you have to use. For evaluating S-matrix elements in vacuum QFT you need the time-ordered propagator (which is identical with the Feynman propagator in vacuum and temperature-0 physics) and the LSZ reduction formalism. In linear-response theory you get the retarded propagator (aka Green-Kubo formulae).
 
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  • #83
Demystifier said:
It is important where the word "spooky" is put. The expression is "spooky action at a distance", not the "action at spooky distance". The expression is used by Einstein to describe features related to the problem of quantum measurement, wave-function collapse, (in)completeness of QM and such. He did not use this expression to describe Newtonian mechanics.
Well, Newtonian physics uses by construction action-at-a-distance interactions, and there's nothing inconsistent with that within non-relativistic physics. The only problem is that it is disproven by experiment. Rather Faraday's and Maxwell's ideas prevailed and has lead to the discovery of relativity in the late 19th to early 20th century.
 
  • #84
ftr said:
Since you deny the physicality of "virtual particles"

You would probably be in the middle of some serious textbook on QFT if you put all this energy in learning instead of low-key arguing about existence of virtual particles.
 
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  • #85
vanhees71 said:
The only problem is that it is disproven by experiment.

What experiment is that. If anything it has been repeated that "virtual particles", Feynman diagrams, propagators .. etc. are all mathematical artifacts.
 
  • #86
weirdoguy said:
You would probably be in the middle of some serious textbook on QFT if you put all this energy in learning instead of low-key arguing about existence of virtual particles.

I wasn't arguing about "VP". Please read the post with the proper context. Anyway, had we only needed to read textbooks we would not need PF which has diverse functions like any other forum.
 
  • #87
ftr said:
What experiment is that.

All of the experiments that confirm General Relativity's predictions where they differ from those of Newtonian physics. Go back and read the post you responded to in its proper context, just as you are asking others to do in your next post.

ftr said:
If anything it has been repeated that "virtual particles", Feynman diagrams, propagators .. etc. are all mathematical artifacts.

Yes, in the sense that we don't directly observe any of these things, they are features of particular theoretical models that make accurate predictions, but those features of the models don't correspond to anything directly observable. But that does not mean that the models overall are not accurate, or that the things that are directly observed are not valid observations.
 
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  • #88
ftr said:
I wasn't arguing about "VP". Please read the post with the proper context.

I'm not sure that helps any. Here is what @weirdoguy quoted from your previous post, preceded by the quote to which it was a response:

A. Neumaier said:
But relativistic QFT has eliminated again the action at a distance.

ftr said:
Since you deny the physicality of "virtual particles" then we are left with just a mathematical relation hinting at nonlocality.

Which has nothing whatever to do with what @A. Neumaier said. The "action at a distance" he referred to has nothing to do with virtual particles at all, much less whether they have "physicality".
 
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  • #89
PeterDonis said:
Go back and read the post you responded to in its proper context

I understood it as forces between charges since he mentioned "Faraday's and Maxwell's ideas", maybe Vanhees can clarify.

AFAIK "VP" has everything to do with electrons interacting(QED). Maybe there is some miscommunication.
 
  • #90
ftr said:
I understood it as forces between charges

Classical action at a distance forces between charges, yes. That's what Faraday and Maxwell's ideas were about (to an extent--they actually thought of the classical electromagnetic field as existing everywhere and the force on one charge being due to the field from another charge, not a direct action at a distance). Nothing whatsoever to do with virtual particles.

ftr said:
AFAIK "VP" has everything to do with electrons interacting(QED).

In the QED model, yes. But the QED model, as has already been pointed out to you, is not an "action at a distance" model. There are no "forces between charges" in that sense in QED. QED is a quantum field theory. "Virtual particles" are an artifact of one particular way of doing calculations in quantum field theory.
 
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  • #91
vanhees71 said:
Since when is string theory physics? SCNR.
Scattering amplitudes in the LHC are calculated using the Parke-Taylor generating function which is a special case of the Witten-RSV formula in Twistor String Theory. If that is not physics, what is?
 
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  • #92
samalkhaiat said:
Scattering amplitudes in the LHC are calculated using the Parke-Taylor generating function which is a special case of the Witten-RSV formula in Twistor String Theory. If that is not physics, what is?
Generalization of physics is not necessarily physics.
 
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  • #93
Demystifier said:
Generalization of physics is not necessarily physics.
String Theory is not a “generalization of physics”, because we were forced to it by the Veneziano amplitude.
 
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  • #94
samalkhaiat said:
String Theory is not a “generalization of physics”, because we were forced to it by the Veneziano amplitude.
String theory is not Veneziano amplitude. String theory is a generalization of Veneziano amplitude. There is no theorem which says that string theory is the only theory which can give Veneziano amplitude. Indeed, since Veneziano amplitude is an (approximative !) description of certain phenomena in nuclear physics, it can be obtained from QCD. And QCD, of course, is not string theory.

Besides (correct me if I'm wrong), I think that perturbative superstring theory does not give Veneziano amplitude. The bosonic perturbative string theory does, but no string theorist thinks that bosonic string theory describes the actual physics.
 
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  • #95
Demystifier said:
String theory is not Veneziano amplitude. String theory is a generalization of Veneziano amplitude. There is no theorem which says that string theory is the only theory which can give Veneziano amplitude. Indeed, since Veneziano amplitude is an (approximative !) description of certain phenomena in nuclear physics, it can be obtained from QCD. And QCD, of course, is not string theory.

Besides (correct me if I'm wrong), I think that perturbative superstring theory does not give Veneziano amplitude. The bosonic perturbative string theory does, but no string theorist thinks that bosonic string theory describes the actual physics.
Don’t make such remarks if you don’t know the technical details. You should at least read something about the history of the Dual Resonance Model and how it led to String Theory.
 
  • #96
samalkhaiat said:
Don’t make such remarks if you don’t know the technical details. You should at least read something about the history of the Dual Resonance Model and how it led to String Theory.
Patronization is not an argument.
 
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  • #97
Demystifier said:
Generalization of physics is not necessarily physics.
But:
Demystifier said:
Anything published in a physics journal is - physics. :wink:
Or do you object to your own arguments?
 
  • #98
PeterDonis said:
There are no "forces between charges" in that sense in QED

I don't understand what you mean by that. Can you elaborate (I don't mind a reference or a technical explanation), thanks.
 
  • #99
A. Neumaier said:
But:

Or do you object to your own arguments?
I am not criticizing the idea that string theory is physics, nor I am criticing the idea that string theory is not physics. Both ideas can be defended by good arguments. But I am criticing the particular arguments (for both ideas) that have been offered here. It is better to have a good argument for a wrong idea than to have a bad argument for a right idea.
 
  • #100
ftr said:
I don't understand what you mean by that.

I meant the same thing that @A. Neumaier meant when he responded to you in post #78.
 
  • #101
Peter Morgan said:
[The difficulty with Hegerfeldt is that none of his many papers are definitively enough stated or proved. Have a look at his paper arXiv:quant-ph/9809030, for example, which I believe is his most recent. Because of the way Hegerfeldt does things, one hears it said that Hegerfeldt only applies to nonrelativistic QM, however it more seems that positive frequency is sufficient, the (stronger) spectrum condition is not required. The connection of positive frequency with analyticity through the Hilbert transform is relatively more elementary than working with the spectrum condition.]

Hegerfeldt's theorem holds under extremely general conditions, including special relativity, as shown, e.g., in his paper G.C. Hegerfeldt, Phys. Rev. D 10, 3320 (1974), so it is certainly not limited to the non-relativistic regime. The theorem basically states that in any first quantized theory an initially localized wave packet with frequency components bounded from below (e.g., an eigenstate of the Newton-Wigner position operator), will, under time evolution, spread out so that it has tails outside the light cone of the initial localized region; thus, a subsequent measurement outside the light cone has non-zero probability of finding that the system has propagated faster than light.

I had the impression that most theorists familiar with the Hegerfeldt theorem believe that this problem is overcome in quantum field theory. For instance,
vanhees71 said:
It's the other way around, and this argument can be found in standard textbooks like Peskin&Schröder: Because time evolution with using √^→p2+m2p→^2+m2\sqrt{\hat{\vec{p}}^2+m^2} as an Hamiltonian in a putative 1st-quantization formulation of relativistic QT (which I call relativistic QM) leads to non-locality and breaks causality even for free fields, one concludes that one has to include the negative-frequency modes into the came, and then the observation of a stable world, i.e., the boundedness of the Hamiltonian of particles from below, forces us to use the 2nd-quantization formulation, i.e., QFT, which I'd call the only physically sensible relativistic QT we know of. It also allows for microcausality and validity of the linked-cluster theorem for the S-matrix, which clearly shows that interactions in QFT are indeed described as local interactions. There are no "spooky actions at a distance" as Einstein thought in the modern formulation of QFT, aka the "Standard Model".

On the other hand,
Peter Morgan said:
I agree with all of this, which is an entirely consistent way of discussing QFT, but it's a perspective that I consider to be laden with conventions. What might be called the "Einstein conventions" are also entirely consistent, and we can rigorously transform from one to the other (arguably this is what is done in my arXiv:1709.06711 for the free EM, Dirac, and complex KG quantum and random fields, which is being not discussed here on PF; I'll propose that the math of the exact transformations there implicitly defines what the Einstein conventions might be), but within the Einstein conventions there is a precise kind of Lorentz invariant nonlocality and other properties are transformed (including that the positivity of the quantum Hamiltonian operator becomes the positivity of the Hamiltonian function). The conventions you are pressing for, almost insisting upon, which might be crudely stated as the Correspondence Principle and all its consequences, have been supremely successful for the last 90 years, but I suggest that a significant part of the progress in our understanding of and in our ability to engineer using quantum physics over the last 30 years, say, has been through considering alternative conventions, in some of which the effective nonlocality of a state can be considered something of a resource.

I am trying to understand where this leaves us. Is the Reeh-Schlieder theorem an analog of the Hegerfeldt theorem for quantum field theory, implying that the causality problems suggested by Hegerfeldt don't go away after all? I have to admit to finding the paper referenced by the original poster, https://arxiv.org/pdf/1803.04993.pdf, difficult, at least on initial reading.
 
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  • #102
Elemental said:
I am trying to understand where this leaves us. Is the Reeh-Schlieder theorem an analog of the Hegerfeldt theorem for quantum field theory, implying that the causality problems suggested by Hegerfeldt don't go away after all?
A restatement, then: from a QFT PoV in which microcausality between measurements being satisfied is the only kind of dynamical locality worth talking about, QFT is dynamically local and there isn't a problem. The nonlocal 2-point and higher correlations that there are in the vacuum (and in modulated form in all states) are just a property of the state, which is not a dynamical nonlocality. This shades us towards superdeterminism, in a quantum mechanical form, but in the QFT context no-one, AFAIK, objects to that in the physics or philosophy of physics literature. If you're willing to adopt that "minimal" QFT PoV, stop now, because it's pretty much adequate.
If, however, we adopt a PoV in which superdeterminism is somewhat objectionable even in a quantum mechanical form (in a classical form superdeterminism is most often taken to be objectionable, but with some exceptions, 't Hooft perhaps being the most well-known), then some or all of the nonlocal correlations presumably have to be accounted for dynamically, albeit whatever we introduce to give that account must, empirically, be Lorentz invariant as an emergent stochastic theory. Empirical considerations further modify this, however, because it's at least for now unclear what experiments we could do to split the nonlocal correlations into superdeterministic and stochastically Lorentz invariant FTL parts — so there's arguably no point worrying about it, we may as well just adopt the "minimal" QFT PoV.
That's not as definitive as you wanted, I'm sure! They do go away, or they don't, depending on what your other commitments are. I'm sure other commitments you might have, not just my choice here of anti-quantum-superdeterminism, could also interact with a commitment to a minimal QFT PoV.
 
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  • #103
Elemental said:
a subsequent measurement outside the light cone has non-zero probability of finding that the system has propagated faster than light.
This is a problem with Born's rule, not with quantum field theory. It shows that at finite times (i.e., outside its use to interpret asymptotic S-matrix elements), Born's rule cannot be strictly true in relativistic QFT. The main reason may be that for interacting QFTs, the particle concept (and hence the Newton-Wigner operator) is only asymptotically valid - i.e., under conditions where particles are essentially free.
See also my posts
https://www.physicsforums.com/posts/5923754/
https://www.physicsforums.com/posts/5926655/
discussing limitations of Born's rule.
 
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  • #104
Peter Morgan said:
If you're willing to adopt that "minimal" QFT PoV, stop now, because it's pretty much adequate.
If, however, we adopt a PoV in which superdeterminism is somewhat objectionable even in a quantum mechanical form (in a classical form superdeterminism is most often taken to be objectionable, but with some exceptions, 't Hooft perhaps being the most well-known), then some or all of the nonlocal correlations presumably have to be accounted for dynamically...

Thanks for the clarifications! Well, I don't think I'll "stop now" because I "know" I have free will, so instead I'll keep plowing through these intractable papers.
 
  • #105
Some interesting papers on physical and conceptual aspects of Reeh-Schlieder theorem:

M. Redhead, The Vacuum in Relativistic Quantum Field Theory, PSA 1994, Volume 2, pp. 77-87

G.N. Fleming, Reeh-Schlieder Meets Newton-Wigner (free pdf can be found by google)

H. Halvorson, Reeh-Schlieder Defeats Newton-Wigner: On alternative localization schemes in relativistic quantum field theory, https://arxiv.org/abs/quant-ph/0007060v1
 
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