Is This the Correct Equation for a Quadratic Involving Points and Distances?

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The discussion centers on finding the correct equation for a quadratic that represents the set of points where the sum of distances from the points (2,0,0) and (-2,0,0) equals 6. The proposed equation, rad[(x-2)^2+(y^2)+(z^2)] + rad[(x+2)^2+(y^2)+(z^2)] = 6, is confirmed as correct but can be simplified. Participants clarify terminology, noting that a "quadric" equation refers to a fourth-degree equation, while the correct term for this context is "quadratic." The conversation emphasizes the importance of accurate mathematical language and simplification in equations. Understanding these concepts is crucial for solving related geometric problems.
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1. Find the equation of the quadric equation that is the set of all points hose sum of their distances from the two points (2,0,0) and (-2,0,0) is 6.

2.I was wondering if rad[(x-2)^2+(y^2)+(z^2)]+rad[(x+2)^2+(y^2)+(z^2)=6 is the equation of the quadric equation?



-vu2
 
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VU2 said:
1. Find the equation of the quadric equation that is the set of all points hose sum of their distances from the two points (2,0,0) and (-2,0,0) is 6.

2.I was wondering if rad[(x-2)^2+(y^2)+(z^2)]+rad[(x+2)^2+(y^2)+(z^2)=6 is the equation of the quadric equation?



-vu2

Hi VU2...

That is correct .But you may simplify it further .
 
Thanks Tanya Sharma for clarifying.
 
Also you are using the wrong word. In English, a "quadric" equation is one that involves a fourth degree of the variable. What you have is a "quadratic" equation.
 
The working out suggests first equating ## \sqrt{i} = x + iy ## and suggests that squaring and equating real and imaginary parts of both sides results in ## \sqrt{i} = \pm (1+i)/ \sqrt{2} ## Squaring both sides results in: $$ i = (x + iy)^2 $$ $$ i = x^2 + 2ixy -y^2 $$ equating real parts gives $$ x^2 - y^2 = 0 $$ $$ (x+y)(x-y) = 0 $$ $$ x = \pm y $$ equating imaginary parts gives: $$ i = 2ixy $$ $$ 2xy = 1 $$ I'm not really sure how to proceed from here.
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