Is water a solvent in this problem?

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In the discussion about the problem of determining the molality of a solution with a mole fraction of water at 0.25, participants clarify the roles of water and methanol as solute and solvent. Water is questioned as a solvent due to its lower mole fraction, but it is established that methanol, with a mole fraction of 0.75, is the solvent in this case. The common rule that the solvent is present in greater amounts is reaffirmed, illustrating that exceptions can occur in specific contexts. The conversation emphasizes understanding mole fractions to accurately identify solute and solvent roles. Ultimately, methanol is confirmed as the solvent in the solution.
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Homework Statement
Determine the molality of a solution of water dissolved in methanol for which the mole fraction of water is 0.25.

Hi all,
I just want to ask if water in this problem is a solvent or a solute!? Is water always a solvent even though they say "a solution of water dissolved in methanol" in the problem? Please help me clear it up.
 
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It appears you've answered your own question. Also, note the mole fraction of water in the solution.
 
naele said:
It appears you've answered your own question. Also, note the mole fraction of water in the solution.

Thanks! Yes, and that's how it get me confused. A solvent is what we have more of, and a solute is what we have less. This appears violating the common rule. I think this is an exception right? what do you think?
 
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That's basically how you look at it. Consider a typical aqueous solution, say 1M HCl. That means there's one mole of HCl in one liter of water. But water is at roughly ~55M so there's quite a bit more of it. In this case, we're told that a water/methanol solution has water at 0.25 mole fraction. By extension we know that methanol has to be 1 - 0.25 = 0.75 which of course is greater than 0.25 so we can only conclude that methanol is the solvent here.
 
Yes, that makes sense to me! Thank so much!
 
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