Is zero positive or negative ?

Analog clocks don't have a second hand for the hour, so for a split second (or infinitesimal moment), both the hour hand and minute hand will be between 12 and 1. So technically, it is neither 12 nor 1 at that moment.
  • #71
micromass said:
No it doesn't. The wiki article implies that 0 is not purely imaginary. I'm pretty sure that is indeed the standard definition.

Well according to your post #11 I was starting to believe in you. Unless you disregard definitions only when it suits your argument. Now you are seeking shelter behind the definitions again.

I believe there is good reason to put the definition aside for a little while and explore consequences. I believe there is good reason to approach zero in different ways in the complex plane.

Example: If we approach 0 using a curve x^(2n +1) for large integer n then close to zero the curve 'hugs' the real axis. From the bottom on the left, from the top on the right.

If we use x^(2n) for large integer n then the curve 'hugs' the real axis from the top on both sides.

If we use y = x then it avoids both axes as I mentioned in a previous post.
 
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  • #72
agentredlum said:
I thought there was a difference I would not write -0 = 0 = +0
Since we both agree there is no difference, and all three are equal, then what is the point of attaching a sign?
agentredlum said:
You do not want to accept the idea that a positive number can be equal to a negative number.
Correct, I do not accept this assertion. The positive numbers are to the right of zero; the negative numbers are to the left of zero. These are two disjoint sets, so there is no number that is in both sets. Therefore, there is no positive number that is equal to any negative number.
agentredlum said:
For real numbers this happens only once
No, it doesn't happen at all.
agentredlum said:
, in the case of zero so it does not have any undesirable consequences for other real numbers. Why is the idea so offensive?
I wouldn't call this idea offensive, but would describe it as nonsensical, for the reason that it goes against the definitions of "positive" and "negative."
 
  • #73
Mark44 said:
Since we both agree there is no difference, and all three are equal, then what is the point of attaching a sign?
Correct, I do not accept this assertion. The positive numbers are to the right of zero; the negative numbers are to the left of zero. These are two disjoint sets, so there is no number that is in both sets. Therefore, there is no positive number that is equal to any negative number.

Well, then you have to put zero in a set all by itself. Why is it better to create a new set instead of putting it in both sets already there?
 
  • #74
What is wrong with the idea that zero is simultaneously a boundary point for both sets (the set of all negative numbers and the set of all positive numbers)?

All other numbers in each set are interior points.

Zero is then required to make this possible.
 
  • #75
agentredlum said:
I believe there is good reason to put the definition aside for a little while and explore consequences. I believe there is good reason to approach zero in different ways in the complex plane.

Example: If we approach 0 using a curve x^(2n +1) for large integer n then close to zero the curve 'hugs' the real axis. From the bottom on the left, from the top on the right.

If we use x^(2n) for large integer n then the curve 'hugs' the real axis from the top on both sides.

If we use y = x then it avoids both axes as I mentioned in a previous post.
These examples are irrelevant in a discussion of whether the real number zero is positive or negative or whether the complex number 0 + 0i is purely real, purely imaginary, or whatever.

What you say about the graphs of y = x2n + 1 and y = x2n, for large n, is true, but so what? You seem to be confusing the ideas of limits with how zero is defined.
 
  • #76
Studiot said:
What is wrong with the idea that zero is simultaneously a boundary point for both sets (the set of all negative numbers and the set of all positive numbers)?

All other numbers in each set are interior points.

Zero is then required to make this possible.

I love your argument, why didn't I think of that?

The boundary of a set is closed. The boundary of a set is the boundary of the complement of the set

I think this link supports your argument.

http://en.m.wikipedia.org/wiki/Boundary_(topology)
 
  • #77
Well to look at it another way

There are three types of points

(1)Interior points where any neighborhood contains only members of the set.

(2)Exterior points where any neighbourhood contains no members of the set.

(3)Boundary points where any neighbourhood contains both members and non members of the set.

Zero satisfies (3)
 
  • #78
micromass said:
No it doesn't. The wiki article implies that 0 is not purely imaginary. I'm pretty sure that is indeed the standard definition.

Are you saying that by the standard definition, 0 is not imaginary? That's interesting ... again, it's only semantic ... but if 0 is not imaginary, what's it doing on the imaginary axis?

The same Wiki article I linked earlier says that the [entire] vertical axis is the imaginary axis. So according to Wikipedia, 0 lies on the imaginary axis but is not imaginary.

Would you regard that as generally agreed upon? In other words if you cornered a half dozen colleagues at faculty tea and asked them if 0 is an imaginary number, what would they say? (Besides, "Micromass, go get us some tea and stop asking silly questions!" :smile:)
 
  • #79
SteveL27 said:
Are you saying that by the standard definition, 0 is not imaginary? That's interesting ... again, it's only semantic ... but if 0 is not imaginary, what's it doing on the imaginary axis?

The same Wiki article I linked earlier says that the [entire] vertical axis is the imaginary axis. So according to Wikipedia, 0 lies on the imaginary axis but is not imaginary.

Would you regard that as generally agreed upon? In other words if you cornered a half dozen colleagues at faculty tea and asked them if 0 is an imaginary number, what would they say? (Besides, "Micromass, go get us some tea and stop asking silly questions!" :smile:)

I think most would say that 0 is imaginary. I know I would say that. But I've seen books where they state "let x be purely imaginary or zero, ...". So I honestly don't know what the standard definition is, but I guess that 0 is not purely imaginary...
 
  • #80
I have to admit to being pretty disinterested in 'the Wiki article'

Surely the nature of 0 depends partly upon the set you are working with?

The integers, rationals, reals etc as do the positive and negative derived sets all include a unique element (0) such that

A + (0) = A for all A

To obtain such a property in the complex domain (where there is no ordering property) you must use (0,0)
 
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  • #81
Studiot said:
Well to look at it another way

There are three types of points

(1)Interior points where any neighborhood contains only members of the set.

(2)Exterior points where any neighbourhood contains no members of the set.

(3)Boundary points where any neighbourhood contains both members and non members of the set.

Zero satisfies (3)

I agree with everything here and can find no fault.

Consider the real number line.

Suppose I believe that zero is neither positive nor negative. Then someone can ask 'what is the complement of the set of positive numbers?' Then I got to put zero in with the negatives.

Suppose again that I believe zero is neither positive nor negative and someone asks 'what is the complement of the set of negative numbers?' Then I got to put zero in with the positives.

So even though I chose to exclude zero, it wound up in both sets anyway contradicting my belief.

Is there something wrong with this line of thought?

If I believe that zero is both positive and negative, then the complement of the positives contains zero and the complement of the negatives contains zero avoiding a contradiction.
 
  • #82
agentredlum said:
If I believe that zero is both positive and negative, then the complement of the positives contains zero and the complement of the negatives contains zero avoiding a contradiction.

Uuuh, if you believe zero to be positive, then the complement of the positives will not contain zero. If you believe zero to be negative, then the complement of the negatives will not contain zero.

This is silly.
 
  • #83
micromass said:
Uuuh, if you believe zero to be positive, then the complement of the positives will not contain zero. If you believe zero to be negative, then the complement of the negatives will not contain zero.

This is silly.

Why did you ignore the word 'both'? an argument made not only by myself but other posters as well.
 
  • #84
agentredlum said:
Why did you ignore the word 'both'? an argument made not only by myself but other posters as well.

I did not ignore the word both. If zero is both negative and positive, then zero is positive, no?
 
  • #85
micromass said:
I did not ignore the word both. If zero is both negative and positive, then zero is positive, no?

yes, of course
 
  • #86
agentredlum said:
yes, of course

So, what is wrong with my post then?

micromass said:
Uuuh, if you believe zero to be positive, then the complement of the positives will not contain zero. If you believe zero to be negative, then the complement of the negatives will not contain zero.

This is silly.
 
  • #87
micromass said:
So, what is wrong with my post then?

You assume that zero will not go in with the negatives, but it must because it is negative also. At the same time, not taken as separate cases.
 
  • #88
agentredlum said:
You assume that zero will not go in with the negatives, but it must because it is negative also. At the same time, not taken as separate cases.

I did not say that. I said: zero is positive, so will not be contained in the complement of the positive numbers. Nothing about negative numbers so far.

It's just because you want the complement of positive numbers to be the negative numbers that there is a contradiction. But in reality, there is no contradiction at all...
 
  • #89
micromass said:
I did not say that. I said: zero is positive, so will not be contained in the complement of the positive numbers. Nothing about negative numbers so far.

It's just because you want the complement of positive numbers to be the negative numbers that there is a contradiction. But in reality, there is no contradiction at all...

Now you're going around in circles.

The assumption is that zero is both, you are assuming zero is ONLY positive.
 
  • #90
agentredlum said:
Now you're going around in circles.

The assumption is that zero is both, you are assuming zero is ONLY positive.

I did not.

Let me break this argument down. Tell me where you disagree

0 is both positive and negative
==> 0 is positive
==> 0 is not contained in the complement of the positive numbers.
 
  • #91
micromass said:
I did not.

Let me break this argument down. Tell me where you disagree

0 is both positive and negative
==> 0 is positive
==> 0 is not contained in the complement of the positive numbers.

Let me make it simple for you. If zero is both positive and negative you must put it in both sets. If it is neither positive nor negative, then it winds up in both sets anyway.

Forget about analyzing HALF a statement, it doesn't work that way.
 
  • #92
agentredlum said:
Let me make it simple for you. If zero is both positive and negative you must put it in both sets. If it is neither positive nor negative, then it winds up in both sets anyway.

Forget about analyzing HALF a statement, it doesn't work that way.

Ok, if it doesn't work that way, then please tell me where I've gone wrong??
 
  • #93
micromass said:
Ok, if it doesn't work that way, then please tell me where I've gone wrong??

0 is both positive and negative
==> 0 is positive
==> 0 is not contained in the complement of the positive numbers.

o-k in line 1 you define zero as both positive and negative

line 2 is vague because one cannot tell whether you mean only positive or you are considering the 2 properties separately

line 3 contradicts line 1 directly regardless of line 2
 
  • #94
agentredlum said:
I agree with everything here and can find no fault.

Consider the real number line.

Suppose I believe that zero is neither positive nor negative. Then someone can ask 'what is the complement of the set of positive numbers?' Then I got to put zero in with the negatives.
The complement of the set of positive numbers is the nonpositive numbers, {x | x [itex]\leq[/itex] 0}, which is the union of the negative numbers and zero. Including zero with the set of negative numbers doesn't mean that zero is negative.
agentredlum said:
Suppose again that I believe zero is neither positive nor negative and someone asks 'what is the complement of the set of negative numbers?' Then I got to put zero in with the positives.
The complement of the set of negative numbers is the nonnegative numbers, {x | x [itex]\geq[/itex] 0}, which is the union of the positive numbers and zero. Just as before, including zero with the set of negative numbers doesn't mean that zero is positive.
agentredlum said:
So even though I chose to exclude zero, it wound up in both sets anyway contradicting my belief.

Is there something wrong with this line of thought?
Yes.
If I buy a bag of apples and a banana at the store, and the checker puts the banana in with the apples, that doesn't mean that the banana has somehow turned into an apple. All it means is that the bag has apples and a banana in it.
agentredlum said:
If I believe that zero is both positive and negative, then the complement of the positives contains zero and the complement of the negatives contains zero avoiding a contradiction.
The only contradictions I see have to do with your flawed understanding of the meanings of the terms positive and negative.
 
  • #95
Mark44 said:
The complement of the set of positive numbers is the nonpositive numbers, {x | x [itex]\leq[/itex] 0}, which is the union of the negative numbers and zero. Including zero with the set of negative numbers doesn't mean that zero is negative.The complement of the set of negative numbers is the nonnegative numbers, {x | x [itex]\geq[/itex] 0}, which is the union of the positive numbers and zero. Just as before, including zero with the set of negative numbers doesn't mean that zero is positive.Yes.
If I buy a bag of apples and a banana at the store, and the checker puts the banana in with the apples, that doesn't mean that the banana has somehow turned into an apple. All it means is that the bag has apples and a banana in it.

Good points, but the last comment is not appreciated by me. I am not the only one supporting that position and I think studiot made an excellent case for it. You found the flaw in my argument overlooked by me. Well done!

You should also send the checker to have his head examined, cause he's mixing apples and bananas.LOL
 
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  • #96
agentredlum said:
Good points, but the last comment is not appreciated by me. I am not the only one supporting that position and I think studiot made an excellent case for it.
I think you are misunderstanding what studiot said. No one else in this thread is seriously arguing (contra the accepted definitions) that zero is both positive and negative.
agentredlum said:
You found the flaw in my argument overlooked by me. Well done!
 
  • #97
{x | x ≤ 0},

I have also been at pains to point out that you cannot use this argument or definition in the complex domain.
 
  • #98
I was always led to understand that zero was devised by Hindu mathematicians as a place filler and borrowed by the western traders and scientists to create our number system using Arabic numerals and getting rid of the virtually impossible to use Roman system that would not usefully allow computation. With the development of set theory it came to denote the empty set. All this huffing and puffing about positive or negative, odd or even, is just trying to count the angels on the point of a needle. Why does it have to have or need such properties? Consider it simply as a place filler in our number sysytem and as denoting not 'nothingness' but the absence of elements in a well defined set, both attributes which seem to me to be identical.
BTW if you have served in the armed forces you will know that they do not have a time of 12 midnight. It is either 23.59 or 00.01.
 
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  • #99
This was the first sentence of my argument.

'Consider the real number line.'

BTW Mark44 'explanation' works ONLY if you accept the definition that zero has no sign. If, for whatever reason, one decides to question that definition, his clever argument doesn't make sense.

Heres what he did...

He took an apple, decided to define it as a banana, then he put it in a bag with other apples and concluded that he now had a bag full of apples and 1 banana. In fact the bag contains only apples. His definition of a particular apple is irrelevant. It is what it is.

The fact still remains that

-0 = 0 = +0

For real numbers, any of the above symbols work.
 
  • #100
agentredlum said:
0 is both positive and negative
==> 0 is positive
==> 0 is not contained in the complement of the positive numbers.

o-k in line 1 you define zero as both positive and negative

line 2 is vague because one cannot tell whether you mean only positive or you are considering the 2 properties separately

I'm considering the 2 properties separetely. You don't really want to argue that "P AND Q ==> P" is false, do you??

line 3 contradicts line 1 directly regardless of line 2

Well, it only contradicts line 1 in your world. As of now, you have still not told me where exactly I've gone wrong here.
 
  • #101
micromass said:
You don't really want to argue that "P AND Q ==> P" is false, do you?

No, this is a tautology. Please post the entire argument then we can discuss it.

Hey, I'm a bit of a rebel, I may question usefulness of certain definitions, but I would never argue against a tautology, that would be silly!
 
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  • #102
agentredlum said:
No, this is a tautology. Please post the entire argument then we can discuss it.

I already posted the argument:

0 is positive and is negative
==> 0 is positive (by the rule "P AND Q ==> P" )
==> 0 is not in the complement of positive numbers (since for each set A, it holds [itex]A\cap A^c=\emptyset[/itex])
 
  • #103
micromass said:
I already posted the argument:

0 is positive and is negative
==> 0 is positive (by the rule "P AND Q ==> P" )
==> 0 is not in the complement of positive numbers (since for each set A, it holds [itex]A\cap A^c=\emptyset[/itex])

line 3 contradicts line 1 in all worlds because if zero is negative you must put it in the set of negative numbers, so it would be in the complement of the positive numbers.
 
  • #104
agentredlum said:
line 3 contradicts line 1 in all worlds because if zero is negative you must put it in the set of negative numbers, so it would be in the complement of the positive numbers.

I don't care. Just tell me where I have gone wrong.
 
  • #105
micromass said:
I don't care. Just tell me where I have gone wrong.

Line 3 does not follow from line 2 if trichotomy property fails for 0.

Where you went wrong is you assumed that trichotomy property holds for zero.

-0 = 0 = +0

What is the point if you don't care?

Trichotomy property holds for all real numbers but for zero it is ill defined because one can write the above equation and it has meaning.

example: -1 = 1 = +1

clearly nonsense

-0 = 0 = +0

not clearly nonsense.
 

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