MHB It is given that the lines intersect. Find the value of a.

  • Thread starter Thread starter Punch
  • Start date Start date
  • Tags Tags
    Vectors
AI Thread Summary
The discussion focuses on finding the value of 'a' for two intersecting lines defined by their parametric equations. To determine 'a', the i, j, and k components of both lines must be set equal, leading to a system of equations. By solving the equations for the parameters r and t, the values can be substituted into the k equation to find 'a'. The intersection condition implies that there will be three equations involving two variables, allowing for a solution. Ultimately, the value of 'a' can be derived through this method.
Punch
Messages
44
Reaction score
0
The equation of the lines l1 and l2 are are r=(4+t)i + (a+3t)j + (2-3t)k and r=(1-2s)i + (1-s)j + (1+s)k respectively, where t and s are real parameters. It is given that the lines intersect. Find the value of a.
 
Mathematics news on Phys.org
Punch said:
The equation of the lines l1 and l2 are are r=(4+t)i + (a+3t)j + (2-3t)k and r=(1-2s)i + (1-s)j + (1+s)k respectively, where t and s are real parameters. It is given that the lines intersect. Find the value of a.

Since the lines intersect, there must be some point where the i, j and k components are all equal. So set them equal to each other and try to solve the system.
 
Notice that you will have three equations in only two variables. Solve the i and j equations for r and t, then put those values into the k equation to determine a.
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...
Back
Top