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Homework Statement
1. An object has a mass of 45kg and is pulled along a horizontal surface by a rope that makes an angle 32 above the horizontal. If the coefficient of friction for the surface is 0.13 and the tension on the rope is 95N what is the acceleration of the object along the horizontal? (0.66m/s is the ans in my textbook)
2. A student is standing 10m from a tall building, if he throws a ball at 12m/s at an angle of 35 up from the horizontal at what height will the ball hit the bulidng (1.92m)
3. [10kg]----[20kg]----> 100N (applied) [weights in boxes]
Given the diagram find the following if the surface has a coefficient of friction of 0.30
Find the accleration of the system (2.06m/s) i keep getting 0.39
Find the tension connecting the 10kg block to the 20kg block (50N)
4. If a student throws and object into the air with a speed of 16m/s at an angle of 25 above the horizontal, if the building is 75m tall how far from the base will the object hit the ground
5. A young woman swims at 2m/s@ 45 S of W for 5 minutes then she swims at 1.5m/s @ 80 E of N for 4 min
What is the average velocity of the woman (40.94 m/min @ 79 S of W ) i can't seem to find this answer
It may seem like alot, but I've tried my best at these questions and can't figure them out please even one will help
@phantom what you see is exactly what i see i can take a picture if you really need the [10kg]--[20kg]---- are boxes being pulled on a rope by 100N applied force
Homework Equations
f= ma
v=d/t
a=v/t
d=vit+1/2at^2
Ff=μ|fg|
The Attempt at a Solution
1. no idea
2. no idea
3. fg+fg+t=ma
a = fg+fg+t/m
fg1 = 10 * 9.81 *.3 = 29.43
fg2= 20 * 9.81 *.3 = 58.86
100N + (-29.43N) + (-58.86N)/30kg = 0.39m/s
Tension if i cannot get accerlation right i can't get the tension right so i didnt even try.
4. no idea
5. 2m/s * 600s = 1200m
1.5 * 240s= 360
(-1200 * cos45 + 360 * cos10)^2 + (-1200*sin45 + 360 * sin10)^2 - than square rooted didnt get the right answer
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