- #1
greg_rack
Gold Member
- 363
- 79
Hi guys,
I have just started studying DEs on my own, so pardonne moi in advance for the probably silly question :)
Via Newton's second law of motion:
$$x''=\frac{F}{m} \ [1]$$
Which is a second-order differential equation.
But, from here, how do I get the good old equation of motion:
$$x(t)=\frac{F}{2m}t^2+vt+x$$
by solving the DE? What is the procedure to apply? In my textbook, only second-order homogeneous DE are treated, but nothing with the form of ##[1]##... and online everything looks over-complicated.
I have just started studying DEs on my own, so pardonne moi in advance for the probably silly question :)
Via Newton's second law of motion:
$$x''=\frac{F}{m} \ [1]$$
Which is a second-order differential equation.
But, from here, how do I get the good old equation of motion:
$$x(t)=\frac{F}{2m}t^2+vt+x$$
by solving the DE? What is the procedure to apply? In my textbook, only second-order homogeneous DE are treated, but nothing with the form of ##[1]##... and online everything looks over-complicated.