Levi-Civita symbol and Kronecker delta

AI Thread Summary
The discussion focuses on proving the relationship between the Levi-Civita symbol and the Kronecker delta, specifically the identity involving determinants. The user seeks guidance on how to demonstrate that the product of two Levi-Civita symbols equals the determinant of a matrix composed of Kronecker deltas. Another participant suggests expanding the determinant to find the connection. The conversation emphasizes the importance of understanding the properties of both symbols in proving the identity. Ultimately, the discussion highlights a common challenge in relating abstract algebraic concepts to concrete mathematical expressions.
typhoonss821
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Hello everyone, I am stuck when I study Levi-Civita symbol.
The question is how to prove

\varepsilon_{ijk}\varepsilon_{lmn} = \det \begin{bmatrix}<br /> \delta_{il} &amp; \delta_{im}&amp; \delta_{in}\\<br /> \delta_{jl} &amp; \delta_{jm}&amp; \delta_{jn}\\<br /> \delta_{kl} &amp; \delta_{km}&amp; \delta_{kn}\\<br /> \end{bmatrix}

where \varepsilon_{ijk} represents Levi-Civita symbol and \delta_{il} represents kronecker symbol.

Thank you very much^^
 
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Have you already established the identity \epsilon_{ijk}\epsilon_{ilm} = \delta_{jl}\delta_{km}-\delta_{jm}\delta_{kl}?
 
Yes I have, but I don't know how to relate it to determinant...
 
Well, you could just write out that determinant and see what happens.
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...

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