- #1
tmt1
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- 0
For this function:
$$\lim_{{x}\to{-\infty}}\frac {x} {\sqrt{x^2}} = -1$$
Why is this correct?
If x is equal to -1, for example, -1 square is 1. And the square root of 1 is 1. So should the answer be 1?
$$\lim_{{x}\to{-\infty}}\frac {x} {\sqrt{x^2}} = -1$$
Why is this correct?
If x is equal to -1, for example, -1 square is 1. And the square root of 1 is 1. So should the answer be 1?