Limit of an Arithmetic Series: Solving for the Limit as n Approaches Infinity

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Limn→∞ (n2/1+5+9+...+(4n-3))
 
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Since you apparently didn't take VietDao's suggestion, I'll tell you the answer is 1/2 and let you figure out if it's correct or not.
 
I have no idea how to do it...so I am asking to give me a clue to this problem!
 
The denominator is an arithmetic series, which sums to 2n2 - n. Therefore the limit is 1/2.
 
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