Limits of Theta and Phi in Surface Integrals on a Sphere

In summary, for a surface integral on a sphere, the limits of theta and phi are 0 to 2pi and 0 to pi respectively. However, this may vary depending on the notation used and the desired coverage of the spherical surface.
  • #1
sunny11119
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I am having problems in finding the limits in surface integral.. for example in case of sphere what will be the limits of theta and phi. somebody please answer quickly. Thanks
 
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  • #2
Welcome to PF!

sunny11119 said:
I am having problems in finding the limits in surface integral.. for example in case of sphere what will be the limits of theta and phi. somebody please answer quickly. Thanks

Hi sunny11119! Welcome to PF! :smile:

theta goes from 0 to π, and phi from 0 to 2π

(or you can do it the other way round :wink:)
 
  • #3
If you are using the standard mathematics notation, where [itex]\theta[/itex] measures "longitude" and [itex]\phi[/itex] measure "co-latitude", then to cover the entires sphere [itex]\theta[/itex] varies from 0 to [itex]2\pi[/itex] and [itex]\phi[/itex] from 0 to [itex]\pi[/itex]. "Engineering notation" reverses [itex]\theta[/itex] and [itex]\phi[/itex]. Of course, if you want to cover only a part of a spherical surface, that's another matter.
 

FAQ: Limits of Theta and Phi in Surface Integrals on a Sphere

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