Lorentz Contraction Circular Motion

In summary: The thing in square brackets is not quite the total differential of T = t + \frac{\omega r^2}{1-\omega^2 r^2}\theta'. I need to think about this a little more. I think you can handle this with Rindler coordinates or something...? Anyway, if you restrict yourself to synchronizing clocks at the circumference of the rotating disc, then the spatial geometry is euclidean in the rotating frame.
  • #36
A.T. said:
They are calculating what http://img688.imageshack.us/img688/4590/circleruler.png" would measure, when placed at rest in the rotating frame. And this ruler is a circle, not a spiral.
Fredrik said:
Yes, but they're doing it by calculating the length of a spiral in spacetime.
That is what they do in chapter 5.1. While in chapter 5.2 they arrive at the non-Euclidean spatial geometry just trough Lorentz contraction. You don't need to consider spirals in space-time to predict what the ruler will measure. In space the ruler is just a circle and it measures spatial distances, which determine the spatial geometry in the ruler's rest frame.

Fredrik said:
The controversial part is to use the term "spatial geometry" about the geometry of a surface that isn't "space".
So in your opinion, rulers at rest in the rotating frame don't measure "spatial geometry" in that frame ? Fine, we can use the term "proper spatial geometry" for what these co-rotating rulers measure, in analogy to "proper length" which is measured by a co-moving ruler.

For me this "proper spatial geometry" is the physically relevant spatial geometry:

If I want to build a huge structure near a massive object, I have to the take the non-Euclidean spatial geometry around the mass into account, when calculating the lengths of the structure's segements.

Analogously:

If I want to build a fast rotating structure, I have to the take the non-Euclidean "proper spatial geometry" in the rest frame of the structure into account, when calculating the lengths of the structure's segements.
 
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  • #37
This paper http://www.phys.uu.nl/igg/dieks/rotation.pdf gives a very nice treatment that I think is both more transparent than Gron's and more directly related to the question that Fredrik and A.T. are debating. There are problems with applying ruler measurements directly to this case, because the rulers are subject to Coriolis and centrifugal forces. You might say that this is no big deal, because we can just use nice, rigid rulers. However, there is a relativistic limit to how rigid the rulers can be. (If they were perfectly rigid, then vibrations would propagate along them at v>c.) If you bring your rulers out to [itex]r=c/\omega[/itex], then their velocity relative to the axis equals the speed of light, which is impossible. Physically, they must be torn apart by centrifugal forces before they get there, even if they are as rigid as relativity allows any material object to be. Even supposing maximum-rigidity rulers, you are going to get dynamical effects at smaller values of r, and therefore you can't use rulers to measure the spatial geometry quite as directly as A.T. is claiming, or as Einstein believed in 1912. The way to get around all these issues is to use radar measurements to establish the spatial geometry, and that requires clock synchronization.

Another way of getting at this is suggested by Wald, near p. 119. When we want to split the metric into separate spatial and temporal parts, with the form [itex](\ldots)dt^2-(\ldots)dx^\mu dx^\nu[/itex], that means we're claiming the spacetime can be put in what's technically known as static (as opposed to stationary) form. Static is more strict than stationary. All static metrics have to have time-reversal symmetry. An example that Wald gives is that a rotating fluid can't have a static metric applied to it. If you want to put material objects like rulers on the disk, they're analogous to the rotating fluid. They have their own stress-energy tensors, etc. You clearly don't have time-reversal symmetry, and therefore you can't measure a static metric using material objects. Again, this can be sidestepped by not using material objects to measure the geometry, but then you have to do clock synchronization.
 
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  • #38
bcrowell said:
This paper http://www.phys.uu.nl/igg/dieks/rotation.pdf gives a very nice treatment that I think is both more transparent than Gron's and more directly related to the question that Fredrik and A.T. are debating.
That's the reference from post #2. It also describes the spatial geometry in the rotating frame as non-Euclidean (Chapter 6) :
The spatial geometry defined by the line element (5) is non-Euclidean, with a
negative r-dependent curvature
And if you do a search on "non-Euclidean spatial geometry rotating frame" you find a lot of references using this interpretation, way back to Einstein:
http://books.google.de/books?id=DH7...idean spatial geometry rotating frame&f=false
bcrowell said:
There are problems with applying ruler measurements directly to this case, because the rulers are subject to Coriolis and centrifugal forces.
The rulers are supposed to be Born rigid as described here: http://books.google.com/books?id=Iy...q=Let us now see how the non-Euclidean&f=true
Which I guess means they are not subject to inertial forces?

BTW: Coriolis force for rulers at rest in the rotating frame?
bcrowell said:
The way to get around all these issues is to use radar measurements to establish the spatial geometry, and that requires clock synchronization.
Can you synchronize rotating clocks along the same r-coordiante and then radar-measure the circumference at r?
 
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  • #39
Re #38 by A.T. -- Ah, thanks for pointing out that you'd already posted a reference to the Dieks paper. I wish I'd paid more attention to you and read it earler :-) I agree with you that the spatial geometry is non-Euclidean -- were you under the impression that I disagreed on that point? Unfortunately the books.google.com links aren't helping me much; their software is blocking me from seeing the relevant parts of the Rizzi anthology and the Gron book, presumably because they want to make sure I don't see too much through the keyhole without paying money. (Well, the Rizzi anthology is only $359 on amazon; maybe we should all buy copies.) Because of that I'm not able to make much of this: "The rulers are supposed to be Born rigid as described here: [...] Which I guess means they are not subject to inertial forces?"

Re Born rigidity, the information I have available is in the Gron paper and the WP article, http://en.wikipedia.org/wiki/Born_rigidity . The thing to realize is that Born rigidity isn't a physically possible attribute of real objects. E.g., the Gron Am. J. Phys. paper (p. 872) says:

"By definition a Born rigid motion of a body leaves lengths unchanged, when measured in the body's proper frame. As made clear by Cavallieti and Spinelli, and by Newburgh, a Born rigid motion is not a material property of abody, but the result of a specific program of forces designed to set the body in motion without introducing stresses. The result of the analysis given above shows that a transition of the disk from rest to rotational motion, while it satisfies Born's definition of rigidity, is a kinematic impossibility. This is the kinematic resolution of Ehrenfest's paradox."

I think you may be under the impression that I'm taking sides with Fredrik in the debate you two have been having. Actually there are some points where I agree with you, and some points where I agree with Fredrik. I agree with you about the non-Euclidean spatial geometry, and that mathematical descriptions need operational definitions to tie them to physical reality.

BTW: Coriolis force for rulers at rest in the rotating frame?
I think Coriolis forces are at least potentially relevant here. If you want to form an operational definition of non-Euclidean geometry in this situation, using rulers, then you have to have some way of comparing radial and azimuthal distances. This requires rotating rulers, and then Coriolis forces will compress or expand the rulers, depending on whether you rotate them in the same direction as the disk's rotation or the opposite direction. If you rotate them slowly enough, you're probably okay, but this is an example of how you really can't get away with ignoring the dynamics of the rulers. The Coriolis force is also what prevents you from transporting a ruler past [itex]r=c/\omega[/itex] along a radial line.
 
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  • #40
bcrowell said:
...and that mathematical descriptions need operational definitions to tie them to physical reality.
You're saying this as if it's something you expect that I'd disagree with. If there's anything in what I've said that suggests that I would, it was 100% unintentional. I was just objecting to the idea that mathematical objects can be defined by statements about physical objects. That's what A.T. seemed to be doing.

An operational definition is something else entirely. It's actually a poorly stated axiom of a theory of physics. For example, the statement "time is what you measure with a clock" is often described as an operational definition of "time", but it isn't really an attempt to define a term. It's an attempt to explain how something in the real world corresponds to something in the mathematical model. To really do that, we at least have to be precise about what mathematical quantity we have in mind. This is how I would say it: "A clock measures the proper time of the curve in spacetime that represents its motion". It's misleading to characterize this statement as a "definition". It's an axiom of a theory of physics.

The statement I used as an example is one of the axioms of special relativity. We clearly need a similar axiom about length measurements, but it's surprisingly hard to state such an axiom in a satisfying way. It's hard enough to write down an axiom that's valid for measuring devices doing inertial motion, and I have no idea what an axiom that's valid for measuring devices in an arbitrary state of motion would look like. I definitely haven't seen one.

That last part is the main reason why I don't like A.T.'s approach. He talks about this stuff as if it's trivial, and it certainly isn't. When we use a method that neither of us understands, the result is likely to be wrong. The standard axioms are however perfectly clear. The geometry of a set of simultaneous events (i.e. "space" at some time t) is Euclidean. I really don't see the point of defining a hypersurface that consists of a bunch of spirals in spacetime and call it "rest space", just so we can describe its geometry as "spatial geometry".
 
  • #41
bcrowell said:
I agree with you that the spatial geometry is non-Euclidean -- were you under the impression that I disagreed on that point?
No I didn't want to imply this. I just wanted to point out that it is something I read in several sources.

bcrowell said:
The thing to realize is that Born rigidity isn't a physically possible attribute of real objects.
The way I understand it: It is an idealized ruler. When measuring with a real ruler you would have to account for the elastic deformations, to calculate the result of the idealized ruler.

bcrowell said:
Gron Am. J. Phys. paper (p. 872) says:
"The result of the analysis given above shows that a transition of the disk from rest to rotational motion, while it satisfies Born's definition of rigidity, is a kinematic impossibility.
"
Two points on this:

1) Do we have to use a solid disk? I proposed a http://img688.imageshack.us/img688/4590/circleruler.png" , which can change it's proper circumference without introducing any tangential stresses. I think it could satisfy Born's rigidity (in the tangential direction) without a kinematic impossibility.

2) Do we have to care about the transition from rest to rotational motion? We could build the rotating ruler from small Born's rigid parts in the rotating state already.

bcrowell said:
This requires rotating rulers, and then Coriolis forces will compress or expand the rulers, depending on whether you rotate them in the same direction as the disk's rotation or the opposite direction.
Okay, that is an issue during transport of the rulers. But once they are at rest in the rotating frame the only problem I see is the centrifugal force. But who says that the centrifugal force has to be countered by the rigidness of the ruler? You could support the structure with small rocket engines facing outwards. The rigid parts from point (2) above don't even have to be fixed to each other, they just use their rockets to form a rotating circle. Then you measure the circumference by counting how many of them you needed.

Another idea: making r very large and omega small (while still keeping a relativistic tangential velocity), should make the centrifugal force sufficiently small.

But all this thinking about how to deal with inertial forces on the rulers seems a bit weird: Don't we have to assume massless rulers anyway? Because otherwise the ruler would also produce gravitation, that could counter the centrifugal force. But we don't want our measuring device to change the scenario and introduce non-Euclidean geometry by it's own mass.
 
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  • #42
Fredrik said:
I really don't see the point of defining a hypersurface that consists of a bunch of spirals in spacetime and call it "rest space", just so we can describe its geometry as "spatial geometry".
If you don't like using the name "spatial geometry" for it, then it is just about semantics. I didn't make this name up.

But I understand the pragmatic reason why this is considered the "spatial geometry in the rotating frame" by many authors, way back to Einstein: The physical consequences of this "rest space geometry" are the same as those in other cases that involve non-Euclidean spatial geometry (e.g. due to a massive object).
 
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  • #43
A.T. -- The thrust of your #41 is that you're proposing a variety of ways of handling the dynamics of the rulers. I would make the following general comments:

This is likely to be extremely difficult and complicated. E.g., the WP article on the Ehrenfest paradox has the following: "1981: Grøn notices that Hooke's law is not consistent with Lorentz transformations and introduces a relativistic generalization." You're going to run into lots and lots of issues like this. It seems like your original motivation for the treatment using rulers was that it seemed conceptually simple, but it looks to me like it is actually much more conceptually complicated than the treatment using light rays.

I have no doubt that it is possible, by picking crafty approximations, to make the dynamical treatment of the rulers work, to some approximation, and that within this approximation you will get the non-Euclidean spatial geometry that we've all been convinced was right ever since Einstein first thought about the example in 1912.

I suspect that the ruler method can achieve either one or the other, but not both, of the following: (1) an exact result, or (2) a method that avoids clock synchronization. The reason is that material rulers can't be used at [itex]r>c/\omega[/itex], so it takes quite a leap of faith to imagine that they could be made to work perfectly at [itex]r=(.999)c/\omega[/itex]. I suspect that if you wanted to use rulers at [itex](.999)c/\omega[/itex], they'd be under so much strain that in order to correct for all the dynamical effects you'd need an explicit model of their behavior in terms of relativistic quantum mechanics. But it seems unlikely to me that a QED model of a ruler can be carried out without dealing with time as a variable, which would obviate the goal of avoiding clock synchronization.

Re Born rigidity, do you have access to the Gron Am. J. Phys. paper? The main point of the paper is that Born rigidity is a kinematical impossibility. E.g., when you say, "You could support the structure with small rocket engines facing outwards," this is exactly the kind of thing that Gron is proving is kinematically impossible, and it's kinematically impossible because of issues relating to clock synchronization.
 
  • #44
Doesn't the ruler method does involve clock synchronization to define the radial direction, ie. the radial line is the line along which clocks can be synchronized?
 
  • #45
atyy said:
Doesn't the ruler method does involve clock synchronization to define the radial direction, ie. the radial line is the line along which clocks can be synchronized?

You can synchronize clocks along a non-straight curve that connects the axis to an off-axis point. You just can't do a global synchronization without discontinuities.

I think the ruler method can be used to define a radial line as the shortest curve connecting the axis with an off-axis point. This does assume that you can locate the axis using nothing but static ruler measurements, but I think that is possible. The Ricci scalar curvature of the spatial metric (which I guess is probably some constant multiple of the Gaussian curvature?) is [itex]R=6/(r^2-2r^2+1)[/itex], where [itex]\omega=1[/itex]. So since you can determine R with static ruler measurements, I think you can locate the axis by looking for where R has a local minimum value of R=6.
 
  • #46
bcrowell said:
The thrust of your #41 is that you're proposing a variety of ways of handling the dynamics of the rulers.
Yes but I end with:
Don't we have to assume massless rulers anyway? Because otherwise the ruler would also produce gravitation. But we don't want our measuring device to change the scenario and introduce non-Euclidean geometry by it's own mass.
Doesn't this make all discussions about problems with inertial forces acting on the rulers kind of pointless?

bcrowell said:
The reason is that material rulers can't be used at [itex]r>c/\omega[/itex], so it takes quite a leap of faith to imagine that they could be made to work perfectly at [itex]r=(.999)c/\omega[/itex].
To determine that the spatial geometry is non-Eclidean it would suffice if they worked at [itex]r=(0.1)c/\omega[/itex].

bcrowell said:
Re Born rigidity, do you have access to the Gron Am. J. Phys. paper? The main point of the paper is that Born rigidity is a kinematical impossibility. E.g., when you say, "You could support the structure with small rocket engines facing outwards," this is exactly the kind of thing that Gron is proving is kinematically impossible, and it's kinematically impossible because of issues relating to clock synchronization.
I will have a look at that. What is the exact title? Or can you summarize his argument?

BTW, This chapter is by Gron as well:
http://books.google.de/books?id=DH7...idean spatial geometry rotating frame&f=false
It deals also with methods to synchronize clocks along a circumference in the rot. frame.
 
  • #47
Won't massless rulers travel at the speed of light?
 
  • #48
bcrowell said:
You can synchronize clocks along a non-straight curve that connects the axis to an off-axis point.

Interesting!

bcrowell said:
I think the ruler method can be used to define a radial line as the shortest curve connecting the axis with an off-axis point. This does assume that you can locate the axis using nothing but static ruler measurements, but I think that is possible. The Ricci scalar curvature of the spatial metric (which I guess is probably some constant multiple of the Gaussian curvature?) is [itex]R=6/(r^2-2r^2+1)[/itex], where [itex]\omega=1[/itex]. So since you can determine R with static ruler measurements, I think you can locate the axis by looking for where R has a local minimum value of R=6.

Operationally, how is a particular "off-axis point" identified?
 
  • #49
atyy said:
Won't massless rulers travel at the speed of light?
I'm just pointing out, that if placing rulers at rest in the rotating frame is seen as problematic due to the rulers' inertia, you could just as well make a problem of the rulers own gravitation curving spacetime. And measuring distances with light doesn't help, because the energy of the light beam curves spacetime as well.
 
  • #50
A.T. said:
I'm just pointing out, that if placing rulers at rest in the rotating frame is seen as problematic due to the rulers' inertia, you could just as well make a problem of the rulers own gravitation curving spacetime. And measuring distances with light doesn't help, because the energy of the light beam curves spacetime as well.

If we assume special relativity then gravity disappears. Not sure about inertial forces though.
 
  • #51
A.T., you should clear the search before you link to a page at Google Books.

Regarding the "massless" rulers, it's sufficient to say that we're talking about what predictions special relativity would make, because spacetime is a fixed mathematical structure (Minkowski spacetime) in that theory. (So neither mass nor anything else has any influence on it).

Edit: I see now that I didn't really need to tell you that. :smile:
 
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  • #52
BTW, I'm a bit mixed up about where the discussion is. Is it that we all agree "something" is non-Euclidean, and the only problem is what that "something" is, and how to demonstrate that an an ideal experiment?
 
  • #53
atyy said:
Is it that we all agree "something" is non-Euclidean, and the only problem is what that "something" is,
That is the semantical part.
atyy said:
and how to demonstrate that an ideal experiment?
That is the physically relevant part.
 
  • #54
atyy said:
BTW, I'm a bit mixed up about where the discussion is. Is it that we all agree "something" is non-Euclidean, and the only problem is what that "something" is, and how to demonstrate that an an ideal experiment?

I think the remaining disagreement is about whether you can determine the spatial geometry by purely static measurements using material rulers, and without clock synchronization.

A few more thoughts:

Suppose you have a ruler that's as rigid as relativity allows (meaning it's less than Born-rigid). You bring it very close to [itex]r=c/\omega[/itex]. Rotations and translations of rulers are necessary in order to carry out these measurements. (If a bunch of rulers are just left in place since the beginning of time, then you have no way to verify that they're all the right lengths in relation to one another.) When this maximally-rigid ruler is oriented radially and positioned near [itex]r=c/\omega[/itex], the speed at which vibrations propagate along it equals c. It's going to vibrate, because you're moving it into place. The vibrations are going to be large, because the ruler is very close to the radius where it would be destroyed by centrifugal forces, meaning that the vibrations almost exceed its elastic limit. You can't just wait for the vibrations to die out, because in the limit of [itex]r \rightarrow c/\omega[/itex], the time dilation becomes infinite, and therefore your thesis adviser (who is back at some smaller value of r) would have to wait an infinite amount of time to hear about the data. The best you can do is to use the propagation of the vibrations to probe the geometry of spacetime. But now the ruler is really just functioning as a sort of waveguide for the electromagnetic fields that bind it together. In other words, all you've done is replace the material rulers with radiometric measurements.

Re clock synchronization, suppose I make measurements with rulers, and I find out that at r=1 m, the Gaussian curvature (as determined from the angular deficit of triangles per unit area) is -1x10^-23 m^-2. I call up a friend, and he says that when he did the same experiment at r=1 m, the Gaussian curvature was -4x10^-23 m^-2. How can we explain the discrepancy? Well, the most likely reason is that he's circling the axis at a frequency that's twice as big as the frequency at which I'm circling the axis. Our measuring apparatus is going around in circles like the hand of a clock, and the problem arose because the hand on his clock was going around at twice the speed at which mine was. So in this sense, you really do need clock synchronization. If there is a physical, rotating "discworld" (with apologies to Terry Pratchet), then all we're doing by bringing the apparatus to rest with respect to the surface of the disk is to synchronize the lab-clock with the discworld clock.

So in summary, I'm convinced that:

(1) Clocks and clock synchronization are necessary, but can be reduced to something relatively trivial. The impossibility of global synchronization is only a big deal because it shows that Born-rigidity is a kinematical impossibility, so you can't have Born-rigid rulers.

(2) Material rulers are probably not nearly as easy to use for this as you'd naively think, even at small r, and at large r it's not even theoretically possible to use them.
 
  • #55
A.T. said:
Now you added a restriction, which also applies to clocks in a rotating frame: You can synchronize clocks which are equidistant to the rotation axis in a rotating frame.

Unfortunately, the whole point I'm trying to make is that you *can't*. To be more specific, you cannot synchronize all the clocks equidistant from the rotation axis according to the Einstein convention. Working your way around the circle, pairwise, when you finally get to the starting point, the last clock you synchronize won't be synchronized with the clock that you started with.

see for instance http://arxiv.org/abs/gr-qc/9805089


the circumference of the disk is treated as a geometrically well defined entity,that
possesses a well defined length without worrying about the fact that no transitive synchronism exists along the said circumference.

Transitive means that if A is sync'd to B, and B is to C, A is syncd'd to C.
 
  • #56
pervect said:
This defines a circumference, but it's not clear that this approach actually defines a "geometry". The "circumference" defined by this means is not a closed curve!

I'm not aware of anyone using this particular approach in the literature - though there may be someone, I'm not familiar with all of the literature on the topic by any means, it's quite large.

For a historical discussion of Einstein's original approach, see p. 11 of this paper: http://philsci-archive.pitt.edu/archive/00002123/01/annalen.pdf To me it seems very close to what A.T. is talking about.

For Einstein's popular-level description of the idea: http://en.wikisource.org/wiki/Relat...easuring-Rods_on_a_Rotating_Body_of_Reference "If, then, the observer first measures the circumference of the disc with his measuring-rod and then the diameter of the disc, on dividing the one by the other, he will not obtain as quotient the familiar number p = 3.14 . . ., but a larger number,[4]** whereas of course, for a disc which is at rest with respect to K, this operation would yield p exactly. This proves that the propositions of Euclidean geometry cannot hold exactly on the rotating disc, nor in general in a gravitational field, at least if we attribute the length I to the rod in all positions and in every orientation."

For a mathematical derivation of the spatial metric: p. 6 of http://www.phys.uu.nl/igg/dieks/rotation.pdf

There is a somewhat different treatment in Rindler's "Relativity: Special, General, and Cosmological" (the long one, not the "Essential" version), p. 198. "The metric of the lattice is the negative of the last three terms in (9.26) and represents a curved three-space..." Amazon will let you peek at the two relevant pages if you use the "look inside" feature and search for "uniformly rotating lattice." Rindler introduces a trick of putting metrics into a certain canonical form, and then uses it in this example. In this canonical form, there's once piece of the metric that's always interpreted as the spatial geometry.
 
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  • #57
bcrowell said:
There is a somewhat different treatment in Rindler's "Relativity: Special, General, and Cosmological" (the long one, not the "Essential" version), p. 198. "The metric of the lattice is the negative of the last three terms in (9.26) and represents a curved three-space..." Amazon will let you peek at the two relevant pages if you use the "look inside" feature and search for "uniformly rotating lattice." Rindler introduces a trick of putting metrics into a certain canonical form, and then uses it in this example. In this canonical form, there's once piece of the metric that's always interpreted as the spatial geometry.

I see - Rindler's p198 does what you were trying to do in post #8.

In a footnote on p72, Rindler agrees with A.T.'s approach (the main points, not sure about not needing clocks): http://books.google.com/books?id=MuuaG5HXOGEC&dq=rindler+relativity&source=gbs_navlinks_s
 
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  • #58
bcrowell said:
You can synchronize clocks along a non-straight curve that connects the axis to an off-axis point. You just can't do a global synchronization without discontinuities.

Let me expand on this a bit...

Global synchronizations *which follow the Einstein convention* don't exist. Someone, possibly AT, is probably going to object "but I can use non-Einstein synchronizations" at some point in the discussion. However, one wouldn't want to use such synchronizations to measure velocities. To illustrate the point, I'll exaggerate it. If one has a jet that takes of at noon in Chicago (CST) and lands at noon in San Diego (PST), it makes no sense to say that it has an infinite velocity because it landed at the same time it took off. Using non-Einstein synchronizations in general needs to be handled carefully to avoid mistakes. Sometimes one can't avoid it, but it is a breeding ground for confusion, and the rotating disk is a prime example of the sorts of confusion that arrise.

It's also possible to mess up distance measurements by using non-Einstein synchronizations, this is more a matter of taking proper care. Personally, I think the best approach for defining distance is to use radar measurements, which is what the SI standard more or less does anyway by defining 'c' as a constant. If we can get a general agreement that any good distance measurement scheme is equivalent to a radar measurement for "close enough" points, I'll feel that we are all on the same definitional page.
 
  • #59
clocks, clocks, clocks
Okay, here another naive idea to determine that space is non-Euclidean, without dealing with clock synchronization issues:

Place three observers at rest in the rotating frame and connect them with laser beams. They will find that the sum of the triangle angles is less than PI and therefore conclude negative spatial curvature.
 
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  • #60
A.T. said:
Okay, here another naive idea to determine that space is non-Euclidean, without dealing with clock synchronization issues:

Place three observers at rest in the rotating frame and connect them with laser beams. They will find that the sum of the triangle angles is less than PI and therefore conclude negative spatial curvature.

Wouldn't one need clocks to define "at rest in the rotating frame", since clocks are needed to define a frame - say first define an inertial frame, there you have clocks, then define a rotating frame relative to that?
 
  • #61
pervect said:
...
Global synchronizations *which follow the Einstein convention* don't exist. Someone, possibly AT, is probably going to object "but I can use non-Einstein synchronizations" at some point in the discussion. However, one wouldn't want to use such synchronizations to measure velocities.

I thought you had better intuition than that, Pervect. You should have known it would be me! :smile: First of all, the Einstein synchronisation method has the explicit assumption that the speed of light is constant and isotropic in all directions. This is clearly not the case as far as a rotating disk is concerned. If a disk is rotating clockwise in the non rotating frame, then a clockwise going light signal sent from a source fixed to the disk, takes longer to go around the perimeter and return to the source than a signal sent from the same source going in the opposite direction. Therefore the speed of light is not isotropic in the rotating frame even when using a single clcok and the Einstein synchronisation method is invalid and simply does not work.
Now we can find a synchronisation method that has the property you described in post 55, of being "transitive". It simply requires all clocks fixed to the perimeter of the rotating disk to be started by a single start signal sent from an omni-directional source located at the axis of the disk. Of course, using such a synchronisation scheme, will mean that the speed of light is not isotropic according to observers in the rotating frame even on a small local scale.


pervect said:
...
It's also possible to mess up distance measurements by using non-Einstein synchronizations, this is more a matter of taking proper care. Personally, I think the best approach for defining distance is to use radar measurements, which is what the SI standard more or less does anyway by defining 'c' as a constant. If we can get a general agreement that any good distance measurement scheme is equivalent to a radar measurement for "close enough" points, I'll feel that we are all on the same definitional page.

The radar method will not work, or at least it will not work any better than the proper distance measurement of space by using rulers at rest in the rotating frame as championed by A.T. For example, if a radar light source located on the rim sends a signal to a mirror located further along the rim of the disk in a clockwise direction, we could adjust the location of the mirror until it takes 2 femto-seconds for the radar pulse to return to the radar source and define the location of the finely positioned mirror as being 1 femto-lightsecond from the radar source. Using this radar method produces identical length measurements to those produced by simply using a ruler at rest with the rotating disk. Additionally we see a failure of the SI standard of defining length as the distance traveled by a light in a given time interval. By timing the period it takes a light signal to go around the perimeter of the disk and return to the source located on the rotating disk, the SI method defines the clockwise circumference to be greater than the anti-clockwise circumference. At least the A.T. proper ruler measurement produces the same distance measurement in either direction. It would seem that your desire for a definition of length that "is equivalent to a radar measurement for 'close enough' points" would be more sympathetic to the proper definition of length as championed by A.T. than the formal definition of length championed by Fredrick.

It would seem that Fredrick has the moral/formal high ground in his definition of spatial distance as being the difference between two events that are measured simultaneously in the a given reference frame and the proper ruler method of measuring the disk circumference does not meet that requirement.

In SR, the purely spatial interval dx is defined as the interval between two events when dt is zero. This definition coincides with proper distance being defined as the distance measured by a physical ruler at rest in the reference frame. This equivalence between spatial interval dx and proper distance breaks down in accelerating reference frames and the arguments in this thread seem to be basically about which method is the better definition of spatial distance in an accelerating reference frame.

Perhaps the arguments in this thread could be made clearer by considering an ideal numerical experiment and asking what the various parties predict the numerical spatial circumference of the rotating disk to be.

Experiment:
Disk radius = 1 light second in the non rotating frame.
Instantaneous velocity of a point of the rim of the rotating disk is 0.8c clockwise, relative to an observer just outside the disk in the non rotating frame.
Gamma = 1/0.6
Circumference = 2*pi*r = 6.28318531 lightseconds in the non rotating frame.

A.T. proper distance circumference:

2*pi*r*gamma = 10.4719755 lightseconds. (Same in both directions.)

Transitive sychronisation method:

Same circumference as A.T. proper distance.

Speed of light is anisotropic (0.555555556 c clockwise and 5.0 c anti-clockwise).

Radar circumference distance (SI standard):

2*pi*r*c/(c-v)/gamma = 18.8495559 lightseconds (Clockwise).

2*pi*r*c/(c+v)/gamma = 2.0943951 lightseconds (Anti-clockwise).

Speed of light is isotropic (c).

Fredrick circumference (dt=zero):

I will let Fredrick work out what this predicts ;)
 
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  • #62
A.T. said:
Okay, here another naive idea to determine that space is non-Euclidean, without dealing with clock synchronization issues:

Place three observers at rest in the rotating frame and connect them with laser beams. They will find that the sum of the triangle angles is less than PI and therefore conclude negative spatial curvature.

I think this still requires local clock synchronization of the relatively trivial type I defined in #54. That is, verifying that the measuring apparatus is at rest with respect to the rotating frame is itself a kind of clock synchronization.

If you want to be able to compare the results with theory, you're also going to need to be able to measure r. The Ricci scalar is [itex]R=-6\omega^2/(1-2\omega^2r^2+\omega^4r^4)[/itex]. The angular excess of a triangle is [itex]\epsilon=\Sigma\theta-\pi[/itex]. The Gaussian curvature is [itex]K=\lim \epsilon/A=R/2[/itex]. So the theoretical prediction you'd need to verify is
[tex]
\lim\epsilon/A = -\frac{3\omega^2}{1-2\omega^2r^2+\omega^4r^4}
[/tex]
To measure r you're going to need something more than a purely local measurement, and the method that would probably realistically work would involve radar and clock synchronization.
 
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  • #63
Kev, re your #61, thanks for going into more detail about clock synchronization. This cleared up some things for me. I was conceiving of the difficulties with clock synchronization as being ones that would only apply to a region that wrapped all the way around in [itex]\theta[/itex]. I can see now that that was incorrect. Measuring the Sagnac effect locally shows that Einstein synchronization fails (or fails to have all the desired properties like transitivity) even locally.

kev said:
The radar method will not work[...]
The radar method for determining the spatial geometry is described by Ø. Grøn, Relativistic description of a rotating disk, Am. J. Phys. 43 869 (1975), at pp. 873-874. The spatial distance [itex]d\sigma[/itex] between two nearby points is defined as half the round-trip time for a beam of light.

kev said:
[...] or at least it will not work any better than the proper distance measurement of space by using rulers at rest in the rotating frame as championed by A.T.
I disagree with you here. There are serious difficulties with using rulers, as described in my #54. Basically you want a Born-rigid ruler, but all you can really have is a ruler that's as rigid as allowed by the fundamental limits that relativity places on the properties of materials. Both Grøn and Dieks ( http://www.phys.uu.nl/igg/dieks/rotation.pdf ) discuss this. For conceptual simplicity, we'd like to be able to describe the spatial geometry as the one that would be measured by rulers. This is what Einstein did in his popularization of GR ( http://en.wikisource.org/wiki/Relat...easuring-Rods_on_a_Rotating_Body_of_Reference ). But in fact that's an oversimplification. Re uniqueness, see Grøn, p. 873, 1st paragraph of section B. Re the issues with the dynamics of actual rulers, see p. 7 of Dieks.

kev said:
Additionally we see a failure of the SI standard of defining length as the distance traveled by a light in a given time interval. By timing the period it takes a light signal to go around the perimeter of the disk and return to the source located on the rotating disk, the SI method defines the clockwise circumference to be greater than the anti-clockwise circumference.
This objection doesn't apply to Grøn's definition. Since [itex]d\sigma[/itex] is defined in terms of round-trip time, you get the same answer regardless of whether you perform the integral [itex]\int d\sigma[/itex] in the clockwise or counter-clockwise direction. One way to see that the difficulty is eliminated is that the Sagnac effect is proportional to the area of the loop, but Grøn's definition uses a loop of zero area.

kev said:
Perhaps the arguments in this thread could be made clearer by considering an ideal numerical experiment and asking what the various parties predict the numerical spatial circumference of the rotating disk to be.
Is there any actual disagreement on this? Grøn's equation 42 on p. 874 for the circumference is equivalent [itex]2\pi R\gamma[/itex], which is what I think everyone agrees is correct. If you go back and look at pervect's #58, he was not proposing anything like the "Radar circumference distance (SI standard)" that you seem to be ascribing to him. He says, 'If we can get a general agreement that any good distance measurement scheme is equivalent to a radar measurement for "close enough" points, I'll feel that we are all on the same definitional page.' The part about "close enough" is clearly equivalent to Grøn's definition, which uses a differential, and inequivalent to what you've labeled "Radar circumference distance (SI standard)."
 
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  • #64
A.T. said:
Place three observers at rest in the rotating frame and connect them with laser beams. They will find that the sum of the triangle angles is less than PI and therefore conclude negative spatial curvature.
atyy said:
Wouldn't one need clocks to define "at rest in the rotating frame", since clocks are needed to define a frame - say first define an inertial frame, there you have clocks, then define a rotating frame relative to that?

Here the setup:

- The mother ship is moving inertially and not rotating, as verified by accelerometers and Sagnac interferometers.

- The mother ship sends out 3 space ships, at 120°-step angles.

- All 3 ships run the same acceleration program, that brings and keeps them in an orbit around the mother ship. Now all 3 are at rest in the same rotating frame.

- Each of the 3 ships is observing the other 2 ships through telescopes and measuring the apparent angle between them.
 
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  • #65
Re # 64 by A.T. -- I think this works fine, except for the issue raised by my #62. If the ships are at [itex]r << c/\omega[/itex], then the angular deficit should equal [itex]-3\omega^2A[/itex], where A is the area of the triangle. But you're going to need some kind of distance measurement in order to determine A, and if you want to test theory at values of r that are not <<c, you'll also need to measure r. It's not a totally static measurement, in the sense that they need to determine [itex]\omega[/itex], which requires clocks. So it seems to me that you can prove the non-Euclidean nature of the geometry by purely static measurements without using radar for distances, but I don't yet see how you can do any kind of quantitative test of theory under those very strict constraints. Maybe you could make a rotating network of triangles, and there could be relationships between the angles in the different triangles?

I think I've now succeeded in clearing up the glitches in the derivation of the spatial metric I gave in my #8. The result is here http://www.lightandmatter.com/html_books/genrel/ch03/ch03.html#Section3.4 , in subsection 3.4.4. I would be grateful for any comments.
 
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  • #66
kev said:
Fredrick circumference (dt=zero):

I will let Fredrick work out what this predicts ;)
Proper length is a coordinate independent property of the curve, so there's nothing to work out. It's 2[itex]\pi[/itex]r.

I haven't seen any comments about an issue that I raised on page 1. We all agree that it's not possible to get a disc spinning without stretching the material, right? When it's streched, the sum of the internal forces on any atom should be towards the center, while the centrifugal force is in the opposite direction. Has anyone worked out which one of these forces "wins"? Does the radius of the disc get larger or smaller when we give it a spin?
 
  • #67
Fredrik said:
I haven't seen any comments about an issue that I raised on page 1. We all agree that it's not possible to get a disc spinning without stretching the material, right? When it's streched, the sum of the internal forces on any atom should be towards the center, while the centrifugal force is in the opposite direction. Has anyone worked out which one of these forces "wins"? Does the radius of the disc get larger or smaller when we give it a spin?

The assumption is that the disc doesn't get bigger or smaller - or we set it up so that it is flat and circular and spinning in the inertial frame - where one needs clock synchronization to verify the "flat, circular and spinning".

For a real disc, I imagine it could warp, so the radius would stay the same, but the disc would not be flat. Or it could break, in which case you could not define a radius. Or ...
 
  • #68
Re: discs that contract when you spin them faster.

There was some discussion of rotating hoops in which I took part - see Greg Egan's webpage http://gregegan.customer.netspace.net.au/SCIENCE/Rings/Rings.html and the link on that webpage back to physics forums. The specific model we analyzed was a "hyperelastic" model.

Under certain conditions the hyperelastic model could predict the radius decreasing as you increased the spin - but this led to some bad behavior, including equations of motion that had no solution (the Lagrangian became singular). I feel now, and I think Greg Egan agrees, that this particular prediction is in a realm where the hyperelastic model fails - one symptom of the failure is the speed of sound exceeding 'c' - though it took some time to notice this.

My own conjecture at this point is that the moment of inertia of the disk must always increase, or you'll get non-physical runaway effects and general bad behavior. If the moment of inerta decreases with increasing angular velocity the disk must spin faster, making it collapse further, making it spin faster, leading to a runaway effect.

Having the moment of inertia not decrease probably implies that the radius also doesn't decrease, it's hard to see how the radius could decrease and the moment of inertia increase. But I haven't analyzed that point very carefully.

But I don't think there's any proof - at this point, I'd just say it's conjecture, though an informed conjecture.
 
  • #69
kev said:
I thought you had better intuition than that, Pervect. You should have known it would be me! :smile: First of all, the Einstein synchronisation method has the explicit assumption that the speed of light is constant and isotropic in all directions. This is clearly not the case as far as a rotating disk is concerned. If a disk is rotating clockwise in the non rotating frame, then a clockwise going light signal sent from a source fixed to the disk, takes longer to go around the perimeter and return to the source than a signal sent from the same source going in the opposite direction. Therefore the speed of light is not isotropic in the rotating frame even when using a single clcok and the Einstein synchronisation method is invalid and simply does not work.

I would agree that the Einstein synchronization method is only possible locally on a rotating frame, and not possible globally.

However, I would disagare that this makes it invalid.

Note that Tartaglia has much the same view, he has influenced my thinking on the topic.


Tartaglia said:
From http://arxiv.org/abs/gr-qc/9805089
It is often taken for granted that on board a rotating disk it is possible to operate a {global}3+1 splitting of space-time, such that both lengths and time intervals are{uniquely} defined in terms of measurements performed by real rods and real clocks at rest on the platform. This paper shows that this assumption, although widespread and apparently trivial, leads to an anisotropy of the velocity of two light beams traveling in opposite directions along the rim of the disk; which in turn implies some recently pointed out paradoxical consequences undermining the self-consistency of the Special Theory of Relativity (SRT). A correct application of the SRT solves the problem and recovers complete internal consistency for the theory. As an immediate consequence, it is shown that the Sagnac effect only depends on the non homogeneity of time on the platform and has nothing to do with any anisotropy of the speed of light along the rim of the disk, contrary to an incorrect but widely supported idea.

Kev said:
Now we can find a synchronisation method that has the property you described in post 55, of being "transitive". It simply requires all clocks fixed to the perimeter of the rotating disk to be started by a single start signal sent from an omni-directional source located at the axis of the disk. Of course, using such a synchronisation scheme, will mean that the speed of light is not isotropic according to observers in the rotating frame even on a small local scale.

Yes, other authors have pointed this out - I don't have the exact reference handy.


The radar method will not work, or at least it will not work any better than the proper distance measurement of space by using rulers at rest in the rotating frame as championed by A.T. For example, if a radar light source located on the rim sends a signal to a mirror located further along the rim of the disk in a clockwise direction, we could adjust the location of the mirror until it takes 2 femto-seconds for the radar pulse to return to the radar source and define the location of the finely positioned mirror as being 1 femto-lightsecond from the radar source. Using this radar method produces identical length

I fail to see why this is bad. The fact that the radar method and the perhaps less-easily defined idea of using rulers arive at the same answer is a plus in my view, suggesting that they both measure what is meant by "distance", as long as the points are close enough.

measurements to those produced by simply using a ruler at rest with the rotating disk. Additionally we see a failure of the SI standard of defining length as the distance traveled by a light in a given time interval. By timing the period it takes a light signal to go around the perimeter of the disk and return to the source located on the rotating disk, the SI method defines the clockwise circumference to be greater than the anti-clockwise circumference. At least the A.T. proper ruler measurement produces the same distance measurement in either direction. It would seem that your desire for a definition of length that "is equivalent to a radar measurement for 'close enough' points" would be more sympathetic to the proper definition of length as championed by A.T. than the formal definition of length championed by Fredrick.

I support keeping the SI notion of distance, and reject the notion of an anisotropic velocity of light. And I'm not quite sure what you are proposing to replace the SI notion of distance? Anyway, if we can't come to an operational agreement on how to measure distance, we have some problems. I was really hoping that everyone would think it was clear that the SI notion was the correct one, at least for nearby points.
 
  • #70
A.T. said:
[re kinematic impossibility of Born rigidity]
I will have a look at that. What is the exact title? Or can you summarize his argument?

Ø. Grøn, Relativistic description of a rotating disk, Am. J. Phys. 43 869 (1975). My shorter presentation of some of the same ideas is here http://www.lightandmatter.com/html_books/genrel/ch03/ch03.html#Section3.4 in subsection 3.4.4, at "Impossibility of rigid rotation, even with external forces."

atyy said:
[re testing R(r)]Operationally, how is a particular "off-axis point" identified?

I would do it by using radar measurements to determine infinitesimal proper distance dr, and then integrating to find r. The "radar ruler" notion of proper distance is defined in the Grøn reference above, and summarized in my own treatment linked to above.

pervect said:
Unfortunately, the whole point I'm trying to make is that you *can't*. To be more specific, you cannot synchronize all the clocks equidistant from the rotation axis according to the Einstein convention.
I think a general statement is that you can synchronize clocks on any open curve, or along any topologically connected set of points that doesn't surround any region with finite area. One way to see this is that the Sagnac effect is proportional to area, and an open curve doesn't enclose any area. Another way to see it is that you can do a chain of Einstein synchronizations, and there will be no self-contradiction if the curve doesn't close back on itself. BTW, the Greg Egan article is a real tour de force! If you were a significant enough contributor to that for him to single you out for credit, then clearly you understand a heck of a lot about this topic.

Fredrik said:
Proper length is a coordinate independent property of the curve, so there's nothing to work out. It's 2[itex]\pi[/itex]r.
Hmm...so are you saying that Rindler, Grøn, and Dieks are all wrong? If so, then it would be interesting to see what you think is the error in their treatments.
 
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