Magnetic equivalent circuit for a UU-core inductor

In summary, the article discusses the development of a magnetic equivalent circuit (MEC) model for a UU-core inductor, which is utilized to analyze its magnetic behavior. It explains how the MEC simplifies the complex magnetic interactions within the inductor by representing them as a network of magnetic reluctances and sources. The model aids in predicting the inductor's performance characteristics, such as inductance and saturation behavior, providing insights for design optimization and improved efficiency in electrical applications.
  • #1
user2539
4
0
Hello, I am trying to develop a magnetic equivalent circuit for a UU-core inductor with two parallel bus bars in the middle of the slot. I am not sure as to how to model the MMF in such problem.
The logical way in my mind is to have two current sources to represent the fields of each bus bar since it is a positive and negative bars it is fair to assume that the fields in the middle would cancel out meaning the rest of the field can be modeled by two current sources in the directions of the each field as the MMF in the equivalent circuit.
Any ideas?
 
Last edited:
Engineering news on Phys.org
  • #2
Welcome to PF.

user2539 said:
Any ideas?
When the UU cores are assembled, they will form a closed magnetic circuit.
UU = O

Will the two bus bars pass together through that loop ?
If so, the equal circuit currents will cancel, resulting in zero field in the UU core.
Between the bus bars, there will be double the magnetic field. The magnetic fields of a return circuit, only cancel at a far distance from both conductors.

Maybe we need a diagram to see what you are considering.
 
  • #3
Baluncore said:
Maybe we need a diagram to see what you are considering.
Agreed!
 
  • #4
1717277225478.png
 
  • #5
That looks like an earth leakage detector or a common-mode choke.

If the currents are equal and opposite, there will be no MMF due to the balanced circuit current.
 
  • #6
It is a common-mode choke, the assumption used is that the currents are not equal.
 
Last edited:
  • #7
user2539 said:
It is a common-mode choke, the assumption used is that the currents are not equal.
Then the simulation model would be a four terminal, two winding transformer, oriented for common mode current. The primary and secondary in that mode are indistinguishable.
 
  • Like
Likes user2539
  • #8
If you know the maximum and minimum currents in the two buss bars and their polarity, you can subtract the minimum from the maximum and use that resultant to size the magnetic circuit.

Cheers,
Tom
 
  • Like
Likes user2539

Similar threads

Replies
4
Views
2K
Replies
25
Views
3K
Replies
15
Views
1K
Replies
2
Views
2K
Replies
43
Views
4K
Replies
4
Views
2K
Back
Top