- #1
tim9000
- 867
- 17
Hi,
I've never thought of an inductor actually consuming any real power, however the other day I was concidering an open circuit secondary, transformer. This should be the same model as just an inductor should it not? (or rather this is how we can model an inductor too?)
If this is so all the current that flows through it flows through the magnetising branch impedance? (To make the circuit, because no current flows into an ideal core) This would mean a tiny current is used to develop flux and a tiny power is dissipated, other than the winding resistance?
Yet there is hardly any power being dissipated in the magnetising branch because the V on the branch is practically at 90deg to the I passing through it?
Is this explanation correct? And does this mean that as the core saturates the magnetisation branch impedance changes? So then the calculated value from the open circuit test value is just an average?
Thanks
I've never thought of an inductor actually consuming any real power, however the other day I was concidering an open circuit secondary, transformer. This should be the same model as just an inductor should it not? (or rather this is how we can model an inductor too?)
If this is so all the current that flows through it flows through the magnetising branch impedance? (To make the circuit, because no current flows into an ideal core) This would mean a tiny current is used to develop flux and a tiny power is dissipated, other than the winding resistance?
Yet there is hardly any power being dissipated in the magnetising branch because the V on the branch is practically at 90deg to the I passing through it?
Is this explanation correct? And does this mean that as the core saturates the magnetisation branch impedance changes? So then the calculated value from the open circuit test value is just an average?
Thanks
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