Magnitude of Momentum, relative to the center of mass

AI Thread Summary
The discussion revolves around calculating the speed of a heavier particle approaching the center of mass of two particles and the momentum of a lighter particle relative to that center of mass. The correct speed for the heavier particle was determined to be 1.29854 m/s. However, the user initially miscalculated the momentum of the lighter particle by not considering its velocity relative to the center of mass. The solution emphasizes the need to calculate the lighter particle's velocity concerning the center of mass for accurate momentum results. The conversation concludes with a clarification on the proper approach to find the correct momentum value.
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Homework Statement


A 4.39 g particle is moving at 4.15 m/s toward a stationary 9.64 g particle.

(a)With what speed does the heavier particle approach the center of mass of the two particles?
Answer in units of m/s.

(b) What is the magnitude of the momentum of the lighter particle, relative to the center of mass?
Answer in units of Ns.

Homework Equations


m1v1+m2v2/m1+m2

and

P=mv


The Attempt at a Solution


I got part (a) by using m1v1+m2v2/m1+m2
where v2 is zero

so I got 1.29854 m/s which is right (this is a online homework assignment)

for part (b) I thought it was the mass of m1= 4.39 g= 0.00439 kg

and I times it by the speed I found from part (a) but the number I'm getting isn't right (0.006402 Ns)

so what am I doing wrong?
 
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You found the speed of the centre of mass with respect to the ground. Calculate the velocity of the lighter particle with respect to the centre of mass.

ehild
 
ehild said:
You found the speed of the centre of mass with respect to the ground. Calculate the velocity of the lighter particle with respect to the centre of mass.

ehild

oh yes, thanks!
 
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