Magnitude of the electric field in a copper wire.

AI Thread Summary
The discussion focuses on calculating the magnitude of the electric field in a copper wire connected to a Nichrome wire within a circuit powered by a 1.5 V battery. Key equations used include the relationship between drift velocity, electric field, and voltage over length. Participants share insights on how to apply these equations, particularly emphasizing the importance of the voltage loop formula and the electron current formula. The solution involves substituting known values to solve for the electric field. This exchange aims to assist others facing similar challenges in understanding electric fields in conductive materials.
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Homework Statement



In the circuit shown, two thick copper wires connect a 1.5 V battery to a Nichrome wire. Each copper wire has radius R = 7 mm and is L = 18 cm long. Copper has 8.4 × 10^28 mobile electrons per cubic meter and an electron mobility of 4.4×10^−3 (m/s)/(V/m). The Nichrome wire is l = 5 cm long and has radius r = 3 mm. Nichrome has 9 × 10^28 mobile electrons/m3 and an electron mobility of 7 × 10^−5 (m/s)/(V/m). What is the magnitude of the electric field in the copper wire? Answer in units of N/C
14e008af-1ee3-40de-a0f2-3a921331ba0d.jpe


Homework Equations



\bar{v}_{thin}=(A_{thick}/A_{thin})\bar{v}_{thick}

\bar{v} = uE

E=V/L

The Attempt at a Solution



I plug in my known values, but I have two unknowns, the electric fields. I'm not sure how to use these equations.
 
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You also know other stuff: that ##2V_{Cu}+V_{Ni}=1.5V## for example.

You also know all kinds of physics about the drift velocity, resistance, current etc. to draw on.
http://en.wikipedia.org/wiki/Drift_velocity
 
I had figured it out for a while now but thanks anyway. I just had to use the electron current formula and the voltage loop formula (as you stated); Plug in numbers, solve for e-field and plug into the other equation.
 
Cool - hopefully someone else stuck on a similar problem will benefit from your question ;)
 
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