Mastering physics: The Electric Field at a Point Due to Two Point Charges

AI Thread Summary
The discussion focuses on calculating the net electric field at the origin due to two point charges: q1 (-4.00 nC) and q2 (+6.00 nC). The user attempted to find the electric fields E1 and E2 using the formula E = K|q|/r^2 but encountered incorrect results. They calculated E1 as 35.95 N/C but expressed confusion about determining the direction of the net electric field relative to the negative x-axis. The conversation emphasizes the importance of considering both magnitude and direction in electric field calculations.
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Homework Statement


A point charge q1:-4.00 nC is at the point x=0.600 meters, y=0.800 meters, and a second point charge q2:+6.00 nC is at the point x=600 meters, y=0 .

a) Calculate the magnitude of the net electric field at the origin due to these two point charges.
Express your answer in Newtons per coulomb to three significant figures.

b) What is the direction, relative to the negative x axis, of the net electric field at the origin due to these two point charges.
Express your answer in degrees to three significant figures.

\phi= _________ (up from the negative x axis)


Homework Equations





The Attempt at a Solution


I tried calculating E1 and E2 and added them both to get E but my answers are wrong
 
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That is the correct way, as long as you take into account the fact that the electric field has a direction as well.

Can you show us how you calculated, for example, E1?
 
i used the equation E=K|q|/r^2. i used these numbers K= 8.988x10^9 q= 4.00x 10^-9 nC
r= square root of: (0.600)^2 + (0.800)^2
and i got E1= 35.95

and for the angle part i have no idea how to do it!
 
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