Material Breakdown Due to Electron Beam

AI Thread Summary
To determine the rate of material breakdown in titanium due to 120 keV electrons, key factors include the electron flux of 8.75e16 electrons per second and the titanium's density of 4.506 g/cm³. The thickness of the titanium is 0.0254 cm, with a surface area of 100 cm². A formula for the attenuation coefficient of electrons based on the atomic number (Z) of the absorber is needed to calculate the average energy deposited per electron or per second. The discussion highlights the importance of understanding energy deposition in materials when subjected to electron beams. Accurate calculations require reliable data on electron interactions with the material.
ajhunte
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The problem asks me to determine the rate of breakdown due to firing 120 kev Electrons at Titanium of arbitrary thickness. I could solve this problem if I knew The average energy deposited per electron, or the Energy efficiency of the entire beam through the titanium.

Given:
Electron Flux (Current)=8.75e16 Electrons per second
Energy of Electrons= 120 keV per Electron
Density of Titanium= 4.506 g per cm^3
Thickness of Titanium= .0254 cm
Surface area of Titanium= 100 cm^2

Is there a formula that accurately describes the attenuation coefficient of electrons (or beta particles) based on the Z (# of protons) of the absorber. I am interested in the average energy deposited per electron or average energy deposited per second.
 
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