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NateTG
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If you mean, "does measuring Alice.a and Bob.b commute even if Alice.a and Alice.b are not commutatively observable?" then the answer depends a bit on which interpretation you chose, and I suppose, on what you mean by commute.DrChinese said:So the question becomes: do you allow non-commuting measurements in a test of the simultaneous reality of non-commuting observables if that is a test on entangled particles? Even though such test is rejected if performed in the form as my (3)?
This is my question, and I am asking for comments. I would guess that the consensus answer would be: yes, it is OK on entangled particles Alice and Bob; but not on Alice alone.
The problem with the definition of commute is that the order of the two measurements can be observer-dependant. So, from that perspective, the order in which the measurements occur cannot matter. On the other hand, from an information point of view, it appears to be the case that when measurement occurs at one particle, information is 'lost' at the other.
My understanding is that some people view such a pair of entangled particles as a single waveform that collapses when measurement occurs at either spatial location - which seems to indicate that the measurements are not commutative. Conversely, AFAICT Bohmian mechanics has no special properties for measurement, so it would appear that from the Bohmian point of view, the measurements are commutative.