Albert said:giving :
(1) $p$ is a divisor of $\dfrac{2000!}{1000!1000!}$
(2) $p$ is a prime
(3) $p$ is a 3-digit number
find $max(p)$
The "Max 3-Digit Prime Divisor" of 2000!/(1000!1000!) is the largest prime number with 3 digits that divides evenly into the number 2000!/(1000!1000!).
To calculate the "Max 3-Digit Prime Divisor" of 2000!/(1000!1000!), you first need to find the value of 2000!/(1000!1000!). Then, you can use a prime factorization method to determine the largest prime number with 3 digits that divides evenly into the result.
Yes, the "Max 3-Digit Prime Divisor" of 2000!/(1000!1000!) is a unique number. Each time the calculation of 2000!/(1000!1000!) is done, the result will be the same, and therefore, the "Max 3-Digit Prime Divisor" will also be the same.
The "Max 3-Digit Prime Divisor" of 2000!/(1000!1000!) can be used in various mathematical applications, such as cryptography and number theory. It is also a useful tool in determining the complexity and efficiency of algorithms.
The "Max 3-Digit Prime Divisor" of 2000!/(1000!1000!) can be both larger or smaller than 1000, depending on the value of 2000!/(1000!1000!). However, it will always be a prime number with 3 digits.