MHB Mechanics- general motion in a straight line

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To calculate the total distance traveled by the robot over 10 seconds, sum the absolute distances moved in each time interval. From t=0 to t=2, the robot moves 2.56m away, then 0.81m back toward the starting position from t=2 to t=5. It moves away again by 0.81m from t=5 to t=8 and returns 2.56m to the starting position from t=8 to t=10. The total distance is 2.56m + 0.81m + 0.81m + 2.56m, resulting in a total distance of 6.74m. Understanding these calculations is essential for analyzing motion in mechanics.
Shah 72
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I don't understand how to find the distance that robot travels in 10s.
 
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t=0 to t=2 … the robot moves away from its starting position 2.56m

t=2 to t=5 … the robot moves back toward its starting position 0.81m

t=5 to t=8 … the robot moves away again from its starting position 0.81m

t=8 to t=10 … the robot moves back to its starting position 2.56m

total distance traveled by the robot would be … ?
 
skeeter said:
t=0 to t=2 … the robot moves away from its starting position 2.56m

t=2 to t=5 … the robot moves back toward its starting position 0.81m

t=5 to t=8 … the robot moves away again from its starting position 0.81m

t=8 to t=10 … the robot moves back to its starting position 2.56m

total distance traveled by the robot would be … ?
Thank you very much!
 

Thread 'Area of Overlapping Squares'

Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?
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