[Mechanics] Tension in bungee jumping

AI Thread Summary
A bungee jumper with a mass of 60 kg jumps from a height of 24 m, with a rope length of 12 m that follows Hooke's law. The energy conservation equation used is mgh = ½kx², where mgh represents gravitational potential energy and ½kx² represents elastic potential energy. The initial gravitational potential energy is calculated using the full height of 24 m, leading to the correct spring constant calculation. The correct spring constant is found to be k = 200 N/m, which differs from the initial incorrect calculation of k = 100 N/m. Understanding the height used in the potential energy calculation is crucial for accurate results.
sushichan
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Homework Statement


A bungee jumper of mass 60kg jumps from a bridge 24 m above the surface of the water. The rope is 12 m long and is assumed to obey Hooke's law. What should the spring constant of the rope be if the woman is to just reach the water?

Homework Equations


Ep=mgh
E=1/2 kx^2

The Attempt at a Solution


Energy conservation? I'm definitely doing something wrong here and not understanding something but I don't know what.

mgh = ½kx^2
(60)(10)(12) = ½k(12)^2
[I put the length of the unstretched part of the rope as my h value and x as the extension, which is 24-12=12]

k= 100 Nm^-1
[This is the answer I got]

But the answer is k=200 Nm^-2
 
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sushichan said:
I put the length of the unstretched part of the rope as my h
To calculate the initial gravitational PE, use the height above the water.
 
Doc Al said:
To calculate the initial gravitational PE, use the height above the water.
okay thanks!
 
This is the key statement : The woman jumps from a bridge 24 m above the surface of water.
 
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