Merging two chambers of identicle gas

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The discussion revolves around merging two identical gas samples in adjacent chambers after removing a thermally insulating partition. The initial conditions include volumes, pressures, and temperatures for each gas sample. To find the final pressure in the merged chamber, the ideal gas law is applied separately to each sample to calculate the number of moles. The final temperature is then related to the total volume and the combined moles of gas. The key takeaway is to express the final pressure in terms of the initial conditions and the final temperature.
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Homework Statement


Two samples of the same ideal gas, x and y, are in adjacent chambers, separated by a thermally insulating partition. The initial volumes, pressures and temperatures of the samples are, Vx, Vy, px, py and Tx, Ty. The partition is removed and the single chamber is brought to a final temperature Tf. If the volume occupied by the partition is negligible, what is the final pressure? (Express your answer in terms of Vx, Vy, px, py and Tx, Ty
and Tf)


Homework Equations


Pv = nRT?


The Attempt at a Solution


I honestly have no idea how to even start this one sorry :/
 
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What does n stand for in that equation?
Perhaps you can apply it first to x and y separately and solve for n?
 
n is the number of moles in the camber
for x: n = \frac{P_xV_x}{RT_x}
for y: n = \frac{P_yV_y}{RT_y}

for the new camber (merged): n = \frac{P_yV_y}{RT_y} + \frac{P_xV_x}{RT_x}

so T_f = \frac{P_f(V_x + V_y)}{(\frac{P_yV_y}{RT_y} + \frac{P_xV_x}{RT_x})R}

but then i still can't get Tf as i don't know pf (pressure in joined container)
 
You are almost there. Please re-read the question carefully. What is your target variable, and which variables should you express it in?
 
oh i was trying to find the wrong thing ^^ oh its easy then thankyou
 
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