Meter stick slides over a meter wide hole at a high speed

In summary, the scenario involves a meter stick sliding along its length towards a hole that is a meter wide in the direction of motion. The stick moves with a speed that results in a gamma factor of 10. In the stick's frame, the hole appears to be 10cm and easily crossable. However, in the hole's frame, the stick appears to be only 10cm and should easily fall in. The question then arises of whether the stick will fall or not, and if so, why. There is a suggestion to consider a simpler paradox, "The Barn and Pole Paradox," and it is noted that a perfectly rigid stick does not exist. The difficulty in analyzing this scenario within the realm of special relativity is acknowledged
  • #36
I think most commenters have lost the point of the OP's original question, which had to do with the apparent paradox of relative lengths (rod and hole) being different in the two frames of reference. Let's do away with gravity, and acceleration, and rotation and bending. How about the surface with the hole being in motion, on a path 90 degrees to the path of the rod? When the rod reaches the hole, can it pass through cleanly or not? The surface is arbitrarily thin and moving plenty fast; the question is how to resolve the conflicting answers in the two frames of reference: Riding along on the surface, one should see a short rod that easily passes through the hole, but riding on the rod, one would see an approaching hole that's too small to get through.
(I think the answer turns out to be that the rod ends up coming in at an angle, which - within limits - allows it to pass through even if it's "too long".)
 
Physics news on Phys.org
  • #37
James Demers said:
I think most commenters have lost the point of the OP's original question, which had to do with the apparent paradox of relative lengths (rod and hole) being different in the two frames of reference. Let's do away with gravity, and acceleration, and rotation and bending. How about the surface with the hole being in motion, on a path 90 degrees to the path of the rod? When the rod reaches the hole, can it pass through cleanly or not? The surface is arbitrarily thin and moving plenty fast; the question is how to resolve the conflicting answers in the two frames of reference: Riding along on the surface, one should see a short rod that easily passes through the hole, but riding on the rod, one would see an approaching hole that's too small to get through.
(I think the answer turns out to be that the rod ends up coming in at an angle, which - within limits - allows it to pass through even if it's "too long".)
That’s a related but different problem. It is worth discussing. To be more precise, consider two problem statements:

1) In a frame with a hole at rest, and a rod moving inertially, oriented parallel to the hole surface in this frame, but with rod trajectory slight skewed from horizontal, a rod with rest length longer than the hole should fit through due to length contraction.

2) In a frame with a rod at rest, and a hole in a surface parallel to the rod in this frame, with said surface and hole moving slightly skewed from horizontal (but surface remaining parallel to rod per this frame), the hole should hit rod in its central region, even though its rest diameter is larger than the rod.

The answer is that these are simply different scenarios, each of which will occur as stated, but each will look different in the rest frame of the other entity.

What distinguishes the rod moving exactly parallel to the hole surface, this being true in both frames, then starting to accelerate through the hole, is that the constraint that the rod not shear, gives a physical preference to the rod initial rest frame. All the rod elements share a common initial simultaneity, and, while starting to change motion, each must not separate from or approach its neighbors.
 
Last edited:
  • #38
James Demers said:
Let's do away with gravity, and acceleration, and rotation and bending.
You can get away from gravity (never a good idea to look at in SR), acceleration, and bending (the bending was an artefact of acceleration). What you cannot get rid of is rotation. Your scenario is similar to the one I described in my first post. If the plane is horizontal and moving up in ”hole” frame, it will not be horizontal in the rod frame.
 
  • Like
Likes James Demers and Sorcerer
  • #39
James Demers said:
I think most commenters have lost the point of the OP's original question, which had to do with the apparent paradox of relative lengths (rod and hole) being different in the two frames of reference. Let's do away with gravity, and acceleration, and rotation and bending. How about the surface with the hole being in motion, on a path 90 degrees to the path of the rod?

In what frame if the path of the hole at 90 degrees to the path of the rod?

If we let ##\vec{v}_h## be the 3-velocity of the hole, and ##\vec{v}_r## be the three velocity of the rod, then the condition that the two velocities be at 90 degrees is that ##\vec{v}_h \cdot \vec{v}_r = 0##

In Newtonian mechanics ##\vec{v}_h \cdot \vec{v}_r## is an invariant. So if ##\vec{v}_h \cdot \vec{v}_r = 0## in one frame, it's zero in all frames. But this is not true in special relativity. The relationship in SR is that ##u_h \cdot u_r## is invaraint, where ##u_h## and ##u_r## are 4-vectors, not 3-vectors.

For those not familiar with 4-vector notation, we can re-write the invariant 4-vector dot product in 3-vector notation as follows, using my favorite sign convention:

$$u_h \cdot u_r = \vec{v}_h \cdot \vec{v}_r -\frac{c}{\sqrt{1- \frac{\vec{v}_h \cdot \vec{v}_h}{c^2}}} \frac{c}{\sqrt{1- \frac{\vec{v}_r \cdot \vec{v}_r}{c^2}}} $$

As a consequence, we can see that the condition that ##\vec{v}_h## and ##\vec{v}_r## be orthogonal, i.e. that ##\vec{v}_h \cdot \vec{v}_r = 0##, depends on one's choice of frame.
 
  • Like
Likes Sorcerer
  • #40
So how about a 15m rod on an inertial tracectory passing two optical through-beam sensors spaced say 10m away from each other, tripping the sensors. The sensors are stationary with respect to each other and they are connected with equally long cables to an ideal AND gate, which in turn powers a signal light.

If the rod moves slowly the signal light will turn on.

What if the rod moves fast enough to appear 5m in the rest frame of the sensors, will the signal light turn on?
 
  • #41
Lord Crc said:
So how about a 15m rod on an inertial tracectory passing two optical through-beam sensors spaced say 10m away from each other, tripping the sensors.
In which rest frame? The rest frame of the sensors? That's what I think you mean here. Is that right?

Lord Crc said:
The sensors are stationary with respect to each other and they are connected with equally long cables to an ideal AND gate, which in turn powers a signal light.

If the rod moves slowly the signal light will turn on.

What if the rod moves fast enough to appear 5m in the rest frame of the sensors, will the signal light turn on?
All I can say is if it the light turns on in one frame, it turns on in the other.

There's also this to consider: if the rod appears 5m in the rest frame of the sensors, how far apart are the sensors in the rest frame of the rod?
Also, what do you mean by "if the rod moves slowly the light will turn on?" Do you mean if the rod moves at a non-relativistic speed with respect to the sensors? If that's the case, then why would it appear to be 5m with respect to the sensors? There wouldn't be any noticeable length contraction if the rod is moving slowly with respect to the sensors.
 
  • #42
Lord Crc said:
The sensors are stationary with respect to each other and they are connected with equally long cables to an ideal AND gate, which in turn powers a signal light.

This means they turn on the signal light when the sensors send signals simultaneously in the rest frame of the sensors. The signal light can still turn on if the signal-sending is not simultaneous in other frames.

Simultaneity is not absolute, but the turning on of the signal light is absolute. If it turns on in one frame it turns on in all frames.
 
Last edited:
  • #43
Lord Crc said:
So how about a 15m rod on an inertial tracectory passing two optical through-beam sensors spaced say 10m away from each other, tripping the sensors. The sensors are stationary with respect to each other and they are connected with equally long cables to an ideal AND gate, which in turn powers a signal light.

If the rod moves slowly the signal light will turn on.

What if the rod moves fast enough to appear 5m in the rest frame of the sensors, will the signal light turn on?

Is this different (and if so how), from the well-known Barn and Pole paradox, about which a lot has been written, some of it in this thread. See also for instance http://math.ucr.edu/home/baez/physics/Relativity/SR/barn_pole.html

Making the "doors" of the barn electronic doesn't make any difference to the problem statement, except for making it a bit more practical.

The resolution is the usual one - the "doors" to the barn are both closed at the same time in the barn frame, but not in the pole frame, due to the relativity of simultaneity.
See the references and other threads for more details.
 
  • Like
Likes James Demers and Sorcerer
  • #44
Lord Crc said:
What if the rod moves fast enough to appear 5m in the rest frame of the sensors, will the signal light turn on?
This appears, as others have said, to be a restatement of the rod and barn paradox. The only addition is transmission lines and an AND gate. As others have noted, if it turns on in one frame it turns on in all. The reason is that the transmission delays are different in a frame where the equipment is moving. In general, if the leading edge of the "sensor activated" pulses moves at speed ±v in the equipment rest frame then it does ##(u\mp v)/(1\mp uv/c^2)## in the moving frame. This will conspire with the changed travel distances to light up the indicator.
 
Last edited:
  • Like
Likes Sorcerer
  • #45
This is a bit of an off topic rant, but I can’t help it...

Special relativity is entirely self consistent. Brilliant minds have been devising new thought experiment tests for it for more than 100 years, and yet it remains self-consistent. Mathematicians have formulated it into a subset of mathematical structures (I believe the term is “manifold”) that show exactly how it is logically self-consistent.

I understand people get confused. I get confused about some aspects of it, too. But what grinds my gears is when someone thinks they’ve discovered a smoking gun that shows it is not self-consistent, as if the mathematicians have not already generalized it and derived every theorem, lemma, and variant imaginable ad naseum.

The only time special relativity is “inconsistent” is the time when the person proposing the thought experiment starts off with an assumption that already violates the well established laws and postulates that define special relativity. In other words, it happens when they create straw man arguments and proceed to tear them down, completely whiffing on their strange desire to prove that special relativity is not self-consistent within its scope of applicability.

As I said twice already, the mathematicians have gotten ahold of it, nearly from the beginning. You can rest assured that they have covered every conceivable contingency and have written thousands of tedious proofs from the most specialized aspects of SR to the most general./end rant.
 
  • #46
Sorcerer said:
This is a bit of an off topic rant, but I can’t help it...

what grinds my gears is when someone thinks they’ve discovered a smoking gun that shows it is not self-consistent

/end rant.

I don't see these thought experiments as attempts to disprove Special Relativity - they're logical puzzles that challenge our ability to think in S.R. terms.
 
  • Like
Likes Nugatory
  • #47
Sorcerer said:
But what grinds my gears is when someone thinks they’ve discovered a smoking gun that shows it is not self-consistent
James Demers said:
I don't see these thought experiments as attempts to disprove Special Relativity - they're logical puzzles that challenge our ability to think in S.R. terms.
You see both. Generally I think people have just missed something. For example, SR is rather less generous in letting you hand-wave over details like the transformation of signal speeds than Newton, which is what I think has caught Lord Crc here.

When someone simply isn't accepting that there is an oversight in their scenario, though, that's what the "report" button is for.
 
  • Like
Likes Sorcerer
  • #48
Ibix said:
You see both. Generally I think people have just missed something. For example, SR is rather less generous in letting you hand-wave over details like the transformation of signal speeds than Newton, which is what I think has caught Lord Crc here.
The biggest hurdle is typically the relativity of simultaneity. For some reason people seem perfectly happy to think about time dilation and length contraction and try to find ”inconsistencies” in those while ignoring the issue of simultaneity, which is crucial for understanding what is going on.
 
  • Like
Likes Sorcerer
  • #49
Orodruin said:
The biggest hurdle is typically the relativity of simultaneity. For some reason people seem perfectly happy to think about time dilation and length contraction and try to find ”inconsistencies” in those while ignoring the issue of simultaneity, which is crucial for understanding what is going on.
Every. Time. Or so it seems when it comes to crackpots I’ve encountered, that is.

But as was said above, not everyone is doing that. A lot of people just want to understand. I just had a moment lol. Too many cranks in one week.
 

Similar threads

Back
Top