Minimum Force to Move 6kg Object on Friction Surface

In summary, the problem involves a 6 kg object on a horizontal surface with a coefficient of friction of .8. The minimum force needed to make the object slide is being calculated, with a focus on the "magic" angle theta that would require the least amount of force to move the object. Using the equations fr = u * N and Fnet,x = F cos theta = fr, and Fnet,y = N - mg + F sin theta = ma, the unknowns N and theta are eliminated to solve for F in terms of theta. Despite the complexity of the problem, the approach is correct and it is advised to keep experimenting with it.
  • #1
uchicago2012
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Homework Statement


A 6 kg object sits on a horizontal surface with coefficient of friction = .8. What is the minimum force (not necessarily horizontal) necessary to make the object slide?

Homework Equations


fr = u * N
where fr = the friction force
u = coefficient of friction
N = the normal force

The Attempt at a Solution


I knew there was something more to this problem- In lecture, my prof talked about a "magic" angle theta in the positive x and positive y direction that would take the least amount of force to move an object is one was pulling on the object at said "magic" angle. Since no value was mentioned, I assume the angle varies with the mass and the force being applied to the object.

As usual for me, I have an apparently sound free body diagram, apparently sound equations, and too many unknowns. I have normal force N, force of gravity mg, friction force fr, and the force on the object F.

Fnet,x = F cos theta - fr = ma
(my prof doesn't believe in the difference between Fk and Fs (static and kinetic friction) so when a = 0 is when the minimum force is being exerted to make the block move)
Fnet,x = F cos theta = fr
Fnet,y = N - mg + F sin theta = ma
acceleration is zero in the y direction so:
F sin theta = mg - N

I can sub in u * N for fr and set tan theta equal to (mg - N) / (u * N), but I don't know N or theta and I'm trying to get to F.

Am I approaching these problems wrong or do I just keep getting lost along the way? I feel like I keep getting stuck in the same places.
 
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  • #2
uchicago2012 said:
Fnet,x = F cos theta - fr = ma
(my prof doesn't believe in the difference between Fk and Fs (static and kinetic friction) so when a = 0 is when the minimum force is being exerted to make the block move)
Fnet,x = F cos theta = fr
Fnet,y = N - mg + F sin theta = ma
acceleration is zero in the y direction so:
F sin theta = mg - N
Looks good to me, so far.

I can sub in u * N for fr
Definitely.

and set tan theta equal to (mg - N) / (u * N), but I don't know N or theta and I'm trying to get to F.
Eliminate N. Solve for F in terms of theta.

Am I approaching these problems wrong or do I just keep getting lost along the way? I feel like I keep getting stuck in the same places.
These are tricky. You're doing fine. Keep playing with it.
 

FAQ: Minimum Force to Move 6kg Object on Friction Surface

What is the minimum force needed to move a 6kg object on a friction surface?

The minimum force needed to move a 6kg object on a friction surface depends on several factors such as the coefficient of friction between the object and the surface, the roughness of the surface, and the angle at which the force is applied. In general, a greater force will be needed to overcome higher levels of friction.

How is the coefficient of friction calculated?

The coefficient of friction is calculated by dividing the force required to move the object by the weight of the object. This value can vary depending on the materials involved and the conditions of the surface.

Is it easier to move a 6kg object on a smooth or rough surface?

In general, it is easier to move a 6kg object on a smooth surface compared to a rough surface. This is because a smooth surface has a lower coefficient of friction, meaning less force is needed to overcome the resistance and move the object.

How does the angle of force affect the minimum force needed to move a 6kg object on a friction surface?

The angle of force can greatly affect the minimum force needed to move a 6kg object on a friction surface. When the force is applied at an angle, only a component of the force is acting against the friction, making it more difficult to move the object. The steeper the angle, the more force will be needed to move the object.

Can the minimum force needed to move a 6kg object on a friction surface ever be zero?

No, the minimum force needed to move a 6kg object on a friction surface can never be zero. Even if the coefficient of friction is very low, there will always be some resistance that requires a force to overcome it and move the object. However, the force needed may be very small in some cases.

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