Multiply infinity by a positive number

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To prove that limXnYn = +∞ given limXn = +∞ and limYn > 0, consider the behavior of the sequences as n approaches infinity. Since limXn = +∞, for any large positive number N, there exists an n such that Xn > N. Additionally, since limYn > 0, there exists a threshold L > 0 such that Yn remains above L/2 for sufficiently large n. By choosing n such that Xn > 2M/L and Yn > L/2, the product XnYn can be made larger than any positive real number M. Thus, it follows that limXnYn = +∞, confirming the initial assertion.
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Homework Statement


Prove that if limXn = +∞ and limYn>0 then limXnYn=+∞


The Attempt at a Solution


limXnYn = limXnlimYn = (c)(+∞) where c is a positive real number

I know in my head that a positive number multiplied by infinity is positive, but I am unsure how to prove this and we have not yet done this particular example in class.
 
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instead of thinking of ∞ as a number, think of:

\lim_{n \to \infty} x_n = \infty

meaning, no matter how large a positive real number N we choose, for all large enough n, xn > N.

now, suppose

\lim_{n \to \infty} y_n = L > 0

for large enough n, we can ensure that yn > L/2 > 0.

can we make xnyn larger than any positive real number M?

(what happens if we pick n so that xnis larger than 2M/L, and yn is larger than _____?)
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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