Need help deriving the general maximum height equation

AI Thread Summary
To derive the general maximum height equation for projectile motion, the formula YMAX can be expressed in terms of initial velocity (Vm), gravitational acceleration (g), and launch angle (θ). Two methods are available for this derivation: a calculus approach using the trajectory equation and a non-calculus approach involving charts. The calculus method requires finding the derivative of the trajectory equation, while the non-calculus method simplifies the process by focusing on vertical motion. Energy conservation principles can also be applied to determine maximum height. Clear and detailed steps must be shown in the derivation to avoid losing points.
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Homework Statement


You need to derive the general maximum height equation for projectile motion. This equation allows you to calculate the maximum height a projectile reaches or could reach during its motion. Like other such equations we derived in this unit, this one is also very short and simple. In this particular equation max height or YMAX can be defined or expressed in terms of Vm, g, θ, and one trig function. there is both a calculus and non-calculus derivation of this particular formula and both require careful and creative thinking.
-The calculus method begins with using the trajectory equation.
-The non-calculus method begins with setting up the charts.

You may choose either method, but you must clearly show every step in the derivation process. Missing or unclear steps will result in a loss of points. Finally clearly write and circle your resulting formula as: YMAX=

Homework Equations


Trajectory Equation: y=xtanθ-(gx2/2VL2cos2θ)


The Attempt at a Solution


After some research I found that the equation should be: YMAX=(Vm2sin2θ/2g)

I really don't even know where to start on this. He said that the non-calculus method is much easier. Any help would be greatly appreciated!
 
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You can split the movement in horizontal and vertical motion and ignore the horizontal part.

Energy conservation is one way to get the maximal height, equations for a free fall will work, too.
In terms of the calculus method: Try to find the derivative of y with respect to x. Which value do you expect at the highest point?
 
Ok, so I split it into Vert and Horiz, then ignored the Horiz. I would get:

Vf = -Vmsin(θ)
Vi = Vmsin(θ)
d = y
t = t
a = g

Is that correct for the chart?

Then I would just have to solve for y and ignore time, using this equation:
Vf2 = Vi2 + 2ad
then
(-VmSin(θ))2=(VmSin(θ))2+2(g)y
but then I run into the problem where y=0. Which is certainly not what I need.

What am I doing wrong?
 
I do not understand what you are doing there.

You could try to calculate the time from launch to highest point, for example.
 
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