Need help on simple binomial problem

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To determine the passing score for a 15-question true-false quiz with less than a 0.10 probability of passing by guessing, the teacher must calculate the binomial probability. The formula involves the binomial coefficient and requires solving the inequality 0.000030518 * [(15!)/(A!)(15-A)!] < 0.10 for A, where A is the number of correct answers needed to pass. The participant is unsure how to handle the factorials in the equation. A solution involves using statistical methods or binomial distribution tables to find the appropriate value for A.
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Hello everyone,

Just have a quick question on a binomial problem.

The problem is as follows:

A teacher is giving a 15 question true-false quiz. He wants to design the quiz such that a person that guesses on all the answers have less than a 0.10 probability of passing. What should the teacher put as the passing number of questions to achieve this?

I have no idea how to do this.
 
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Suppose you call the number of correct responses needed to pass a. If X is the number of correc responses from 15 guesses, what must be the relation between X and a in order to pass?
 
I have my test in half an hour and that was the only question I didnt know how to do from the review.

So let A be the number needed to pass, then:

P(A) = 15_C_A * (0.5)^A * (0.5)^(15-A) = 15_C_A * (0.5)^15 = 0.000030518 * 15_C_A = 0.000030518 * [(15!)/(A!)(15-A)!]

and since I want P(A) < 0.10 then:

0.000030518 * [(15!)/(A!)(15-A)!] < 0.10

and solve for A? (no idea how to solve involving a factorial like that) Is this the way to go about this? A quick response will be appreciated :)
 
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