Need Help Solving, Expanding, Rewriting, Graphing Logarithmic Functions

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  • #1
constant constant
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Homework Statement
Solving, Expanding, Rewriting, Maybe Graphing? Logarithmic Functions. :)
Relevant Equations
Here are some equations if you find that easier:

log8(2) + log8(24) - log8(5) = 27

log3(34)

Why not throw in an exponential:

Where,

_ = coefficient

^ = exponential

4e^2k + 1_ + 3 = 27
I personally have no need for picture examples on this. But if you wish, I may. I was curious if anyone wanted to enlighten me with different methods to either rewrite, solve, expand, or even graph logarithmic functions. Sorta big ask. Though, it would be very refreshing. I myself have some understanding. But I've been studying by myself (against better judgement). It's very unclear where to start making a readable study guide so that's why I'm here.
 
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  • #2
If you use tex I will know you better. e.g.
[tex]\log_8 2=\frac{1}{3}[/tex]
 
  • #3
constant constant said:
Homework Statement: Solving, Expanding, Rewriting, Maybe Graphing? Logarithmic Functions. :)
Relevant Equations: Here are some equations if you find that easier:

log8(2) + log8(24) - log8(5) = 27

log3(34)

Why not throw in an exponential:

Where,

_ = coefficient

^ = exponential

4e^2k + 1_ + 3 = 27

I personally have no need for picture examples on this. But if you wish, I may. I was curious if anyone wanted to enlighten me with different methods to either rewrite, solve, expand, or even graph logarithmic functions. Sorta big ask. Though, it would be very refreshing. I myself have some understanding. But I've been studying by myself (against better judgement). It's very unclear where to start making a readable study guide so that's why I'm here.
:welcome:

PF isn't all that good at rewriting textbooks, but there is plenty of material in the Science and Math Textbooks Forum so please have a look around there and see if there is something that suits you.

I suspect english is not your first language, and it's not all that clear to me what exactly it is that you are asking. Do you want us to solve your equations ? Provide a study guide? Make plots ?

Please clarify

##\ ##
 
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  • #4
constant constant said:
Here are some equations if you find that easier:

log8(2) + log8(24) - log8(5) = 27
Using LaTeX, this equation can be written as ##\log_8(2) + \log_8(24) - \log_8(5) = 27##

If you're studying log equations, you need to become familiar with the properties of logs, such as ##\log_b(x) + \log_b(y) = \log_b(xy)## and ##\log_b(x) - \log_b(y) = \log_b(\frac x y)## and several others. There are restrictions on the possible values of the base b as well as the variables used here.
constant constant said:
log3(34)
This one is not an equation since there is no = symbol. It's an expression that you're supposed to simplify or expand. Not sure what you are supposed to do with this as there's no obvious simplification.
constant constant said:
Why not throw in an exponential:
Where,
_ = coefficient
^ = exponential

4e^2k + 1_ + 3 = 27
This equation is very ambiguous, as written. I don't know what you mean by "_ = coefficient". I think the above is intended to be ##4e^{2k + 1}+ 3 = 27##.
The best approach would be to get this equation into the form ##e^{\text{ expr1 }} = \text{expr2}## and then take the natural log (##\ln##) of both sides of the equation.
constant constant said:
I personally have no need for picture examples on this.
What do you mean by "picture examples"?
 
  • #5
Thanks! It kinda made me realize I know more of what I'm doing. So that's nice! To anyone who was confused, I'm just trying to get used to the formatting of this forum (that's why equations were unclear). And I know English lol, I just don't know how to speak on forums. Again, thanks! (for all the feedback and improvements)
 
  • #6
constant constant said:
Thanks! It kinda made me realize I know more of what I'm doing. So that's nice! To anyone who was confused, I'm just trying to get used to the formatting of this forum (that's why equations were unclear). And I know English lol, I just don't know how to speak on forums. Again, thanks! (for all the feedback and improvements)
Will try to be more clear in the future
 

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