Need to calculate current flowing through parallel resistors.

In summary: Also, if you were to add them all together, you would be proceding down the path as mentioning in a), rather than b).Using Rt = 1/(1/R1 + 1/R2 + ... + 1/Rn) will allow you to find the total resistance of resistors in parallel, but there are multiple different sets of parallel resistors in this diagram so be careful with the math. Also, if you were to add them all together, you would be proceding down the path as mentioning in a), rather than b).Lets go with b) instead.
  • #36
Zryn said:
Yes you can, that is the correct answer and the discrepancy is only due to rounding errors.

The current divider that you were going to end up with is as follows:

Ir = Rt / (Rt + Rn) * I

Ir4 = (R3||R5||R6) / (R3||R5||R6 + R4) * I

Ir4 = [ 1 / (1/R3 + 1/R5 + 1/R6) ] / { [ 1 / (1/R3 + 1/R5 + 1/R6) ] + R4 } * I

Ir4 = [ 1 / (1/90 + 1/70 + 1/60) ] / { [ 1 / (1/90 + 1/70 + 1/60) ] + 80 } * 0.337

Ir4 = 23.77 / ( 23.77 + 80 ) * 0.337

Ir4 = 0.229 * 0.337

Ir4 = 0.077

I have a quick question, how do you calculate Collector emitter resistance?
 
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  • #37
It's best to start a new thread with any diagrams, equations and workings you have.
 

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