- #1
Please post your answers to parts a and b.mustafamistik said:Homework Statement:: It's not Homework.
Relevant Equations:: F=m*a
I did part a and part b but stuck in part c. Could you help me?
I edited. You can help even if you tell me a solution way. Cause I don't even know what to do .haruspex said:Please post your answers to parts a and b.
You are missing a force on m1.mustafamistik said:I edited. You can help even if you tell me a solution way. Cause I don't even know what to do .
Is it Friction force ?haruspex said:You are missing a force on m1.
Yes.mustafamistik said:Is it Friction force ?
Thanks. Could you give a hint for part c?haruspex said:Yes.
Think about the maximum acceleration that is possible with the given coefficient of friction.mustafamistik said:Thanks. Could you give a hint for part c?
friction-m*g*sin(16)=m*aPeroK said:Think about the maximum acceleration that is possible with the given coefficient of friction.
It's hard to make sense of that out of context. Please describe what you are trying to say with that equation.mustafamistik said:friction-m*g*sin(16)=m*a
Is this equation true ?
This equation to find maximum acceleration. (m2*g*cos(16)* μ) -(m2*g*sin(16))=m2*a (F=ma)PeroK said:It's hard to make sense of that out of context. Please describe what you are trying to say with that equation.
Okay, and the mass cancels out, of course.mustafamistik said:This equation to find maximum acceleration. (m2*g*cos(16)* μ) -(m2*g*sin(16))=m2*a (F=ma)
I think,PeroK said:Okay, and the mass cancels out, of course.
What is the relationship between the large mass, ##M##, and the acceleration of ##m_2##?
How are you getting that from Newton's Laws? What are you wrongly assuming?mustafamistik said:##T=M*g ##
Is it wrong? I don't understand.haruspex said:How are you getting that from Newton's Laws? What are you wrongly assuming?
Answer my question: which of Newton's Laws did you use to write the equation?mustafamistik said:Is it wrong? I don't understand.
I used Newton's Second Law.haruspex said:Answer my question: which of Newton's Laws did you use to write the equation?
Which says..?mustafamistik said:I used Newton's Second Law.
F=maharuspex said:Which says..?
And what is a for the mass M?mustafamistik said:F=ma
g? I get it its not. We should consider all the system. Am i right ?haruspex said:And what is a for the mass M?
That would be free fall.mustafamistik said:g? I get it its not
They are same.haruspex said:That would be free fall.
What is the relationship between M's acceleration and the acceleration of the masses on the slope?
Right. And what is the net force on M?mustafamistik said:They are same.
(M*g)-((m_1+m_2)*g*sin(16)) ?haruspex said:Right. And what is the net force on M?
Only consider the forces that act directly on M. What are they?mustafamistik said:(M*g)-((m_1+m_2)*g*sin(16)) ?
Gravitational force and Tharuspex said:Only consider the forces that act directly on M. What are they?
Right, so write out the ΣF=ma equation for the mass, putting the sum of those forces on the left and its mass times acceleration on the right. Careful with signs.mustafamistik said:Gravitational force and T
##(M*g)+(m_1+m_2)*g*sin(16) =M*a##haruspex said:Right, so write out the ΣF=ma equation for the mass, putting the sum of those forces on the left and its mass times acceleration on the right. Careful with signs.
As you correctly stated in post #28, the forces that act on M are gravity and the tension. Those are the only forces that should appear in the equation. Yes, it may turn out that the tension is equal to ##(m_1+m_2)*g*\sin(16) ##, but take it one step at a time.mustafamistik said:##(M*g)+(m_1+m_2)*g*sin(16) =M*a##
T= ##(m_1+m_2)*g*\sin(16) ##haruspex said:As you correctly stated in post #28, the forces that act on M are gravity and the tension. Those are the only forces that should appear in the equation. Yes, it may turn out that the tension is equal to ##(m_1+m_2)*g*\sin(16) ##, but take it one step at a time.
And think about the way each force acts on M.
It doesn't matter which direction you take as positive as long as you are consistent. The important point is that tension and gravity are acting in opposite directionsmustafamistik said:T= ##(m_1+m_2)*g*\sin(16) ##
Gravity = M*g
Tension and Gravity are opposite forces. So we should consider the Gravity negative?
I get it thanks sir. But i don't know how to calculate max M still.PeroK said:It doesn't matter which direction you take as positive as long as you are consistent. The important point is that tension and gravity are acting in opposite directions
Let's take a step back. If there is no slipping between ##m_1## and ##m_2##, then we have a simple pulley system with a mass ##M## pulling a mass ##m_1 + m_2## up a slope.mustafamistik said:I get it thanks sir. But i don't know how to calculate max M still.