- #1
SteliosVas
- 70
- 0
Homework Statement
Attached is a image of the circuit that I am attempting to analyze:
Homework Equations
KCL
The Attempt at a Solution
So I know I should assign a place in the circuit where I should preform KCL after selecting a reference point.
I selected the reference point as the 2ohm resistor with the right hand side being V2 and the left as V1
Would the KCL at v1 be:
-4+(v1-8)/2+(v1-v2)/2 =0
and KCL at v2 be:
(v2-v1)/2 + v2/4 =0
But I didn't get the right answer. I have not sure now...