- #1
binbagsss
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I am trying to follow the following post.
[Mentors' note: The "following post" is from https://physics.stackexchange.com/q...onservation-law-corresponds-to-lorentz-boosts]
I dont understand how they have got the expression for the current for translations from the general expressions for the current. so from what I see from the ##\delta x^{\mu}## stated for a translation , they are saying into the above substitute ##a^{\nu}=\delta^{\mu}_{\nu}## into the general expression. But obviously this is not what it is saying as this would not give me the right expression.
Thanks
[Mentors' note: The "following post" is from https://physics.stackexchange.com/q...onservation-law-corresponds-to-lorentz-boosts]
I dont understand how they have got the expression for the current for translations from the general expressions for the current. so from what I see from the ##\delta x^{\mu}## stated for a translation , they are saying into the above substitute ##a^{\nu}=\delta^{\mu}_{\nu}## into the general expression. But obviously this is not what it is saying as this would not give me the right expression.
Thanks
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