Normalization constant A of a harmonic oscillator

AI Thread Summary
The discussion centers on the normalization constant A for a harmonic oscillator's wavefunction, where the user encounters an undefined result of 1/0 while attempting to normalize the wavefunction. Confusion arises regarding the proper application of absolute values and the calculation of the modulus of complex numbers. Participants clarify that the absolute value of a sum does not equal the sum of the absolute values, and emphasize the correct method to calculate the modulus. The conversation highlights the importance of correctly multiplying complex wavefunctions to derive the normalization condition. Understanding these mathematical principles is crucial for resolving the normalization issue.
Sorin2225
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Homework Statement
Finding the normalization constant A of a harmonic oscillator
Relevant Equations
(psi(x,t))^2=1
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I've worked through it doing what I thought I should have done. I normalized the original wavefunction(x,0) and made it = one before using orthonormality to get to A^2(1-1) because i^2=-1 but my final answer comes out at 1/0 which is undefined and I don't see how that could be correct since A is meant to be a real number. I'm not really sure where I've gone wrong either so any insight would be appreciated.
 
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##\lvert \psi_1 + i \psi_4 \rvert^2 \ne (\psi_1 + i \psi_4)^2##

The vertical lines matter.
 
So it's the absolute value? which means that it's +1 not -1?
 
What is “it”?
 
|iψ4*iψ4|
 
That's not how absolute values work. You can't say ##\lvert a+b \rvert = \lvert a \rvert + \lvert b \rvert## in general.

How do you calculate the modulus of a complex number?
 
sqrt(a^2+b^2) so it would be Sqrt((i^2)^2+((psi(4)^2)^2))
 
##|\Psi|^2=\Psi^*\Psi=[A(\psi_1+i\psi_4)][A^*(\psi^*_1-i\psi^*_4)]##. What do you get when you multiply it out?
 
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