- #1
HighPhy
- 89
- 8
The other day my computer science professor gave an advanced course on the importance of quantum computers.
At one point, he justified the fact that quantum computers have unlimited functions by saying that with ##800## qubits we could (he does not say "we can") represent the entire universe.
What are the arguments in favor of that thesis? Where did the number ##800## come from?
What I don't understand is the deeper meaning of the number of qubits needed to simulate/describe the universe. AFAIK, the idea is that the observable universe can only have ##2^n## possible states. And a quantum computer with ##n## qubits can have ##2^n## possible states. So a quantum computer with ##n## qubits must have a state that described the entire observable universe.
Googling suggests that now QCs with 1000 qubits have been made, so what's the point? I'm really struggling.
Moreover, the number ##800## does not prove me convincing. If ##2^n## are the possible representable states, ##3.57 \times 10^{80} \ \mathrm{m^3}## is the volume of the observable universe, and ##(1.616 \times 10^{-35})^3 \ \mathrm{m^3}## is the Planck length cubed, the number of qubits would be given by $$\log_2 \left(\dfrac{3.57 \times 10^{80}}{(1.616 \times 10^{-35})^3}\right) = 615 \ \mathrm{qubits}$$ Not ##800##.
Another point of confusion.
At one point, he justified the fact that quantum computers have unlimited functions by saying that with ##800## qubits we could (he does not say "we can") represent the entire universe.
What are the arguments in favor of that thesis? Where did the number ##800## come from?
What I don't understand is the deeper meaning of the number of qubits needed to simulate/describe the universe. AFAIK, the idea is that the observable universe can only have ##2^n## possible states. And a quantum computer with ##n## qubits can have ##2^n## possible states. So a quantum computer with ##n## qubits must have a state that described the entire observable universe.
Googling suggests that now QCs with 1000 qubits have been made, so what's the point? I'm really struggling.
Moreover, the number ##800## does not prove me convincing. If ##2^n## are the possible representable states, ##3.57 \times 10^{80} \ \mathrm{m^3}## is the volume of the observable universe, and ##(1.616 \times 10^{-35})^3 \ \mathrm{m^3}## is the Planck length cubed, the number of qubits would be given by $$\log_2 \left(\dfrac{3.57 \times 10^{80}}{(1.616 \times 10^{-35})^3}\right) = 615 \ \mathrm{qubits}$$ Not ##800##.
Another point of confusion.
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