Object moving in equilateral triangle - magnitude of acceleration

AI Thread Summary
An object moves with a constant speed of 22.3 m/s around an equilateral triangle, completing the path in 12.69 seconds. The average acceleration vector's magnitude is calculated using vector components and relevant equations. The solution involves breaking down the motion into x and y components. The final calculated average acceleration is 3.04 m/s². This demonstrates the relationship between constant speed and changing direction in circular motion.
physos
Messages
2
Reaction score
0

Homework Statement


An object moves around a equilateral triangle with a constant speed (magnitude of velocity is constant) of 22.3 m/s. If it moves from the starting to ending point (as shown below) in a time of 12.69 seconds, what is the magnitude of the average acceleration vector in m/s2?



Homework Equations



V\DeltaV= (rFx-rix/delta(t)) - (rfy-riy\delta (t))


The Attempt at a Solution

 
Physics news on Phys.org


Break the vector into x and y components then use the equation:
(delta)y=v0t-(1/2)gt^2
 


Thanks! i figured out the answer.. its 3.04
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Struggling to make relation between elastic force and height'
Hello guys this is what I tried so far. I used the UTS to calculate the force it needs when the rope tears. My idea was to make a relationship/ function that would give me the force depending on height. Yeah i couldnt find a way to solve it. I also thought about how I could use hooks law (how it was given to me in my script) with the thought of instead of having two part of a rope id have one singular rope from the middle to the top where I could find the difference in height. But the...
Back
Top