tkhunny said:Well, what did you do first? You'll have to get Ru out of the denominators.
Two different denominators? I'm guessing you'll need your Quadratic Formula. Can you figure out which solution will be acceptable?
While you were able to see it more quickly, I've finally come to the same conclusion. I was able to put the equation in a quadratic form, equal to zero. Thank you for your help.Joppy said:Welcome to MHB!
Hint: I would try grouping the RHS into a single fraction (find a common denominator), and then 'crank the handle'. i.e. multiply and group terms, you should end up with a quadratic in $R_{\rm u}$.
Edit: whoops, tkhunny beat me to it!
Outdoors said:While you were able to see it more quickly, I've finally come to the same conclusion. I was able to put the equation in a quadratic form, equal to zero. Thank you for your help.
All the previous approaches were messy. The approach that led to the quadratic form was clean. It all took way too long though. Rusty I guess.tkhunny said:Good work! Was it messier than you expected?
Perfect. Hang in there. You're getting back up to speed already!Outdoors said:All the previous approaches were messy. The approach that led to the quadratic form was clean. It all took way too long though. Rusty I guess.
"Ru" represents the unknown resistance value that needs to be isolated.
To isolate "Ru", you can use algebraic manipulation to rearrange the equation and solve for "Ru".
Yes, the equation can be simplified by combining like terms and using the distributive property.
Yes, the equation can be solved for multiple values of "Ru" as long as the other variables are known.
This equation can be used to calculate the unknown resistance value in a circuit, which can be useful in various scientific experiments involving electricity and electronics.