On length contraction (Special Relativity)

AI Thread Summary
Length contraction in special relativity transforms a sphere in motion into an oblate spheroid, with the equatorial radius contracting by a factor of gamma (γ) while the polar radius remains unchanged. The volume of the original sphere decreases due to this contraction, leading to a new volume calculation for the oblate spheroid. Confusion arises regarding whether the equatorial or polar radius is affected by contraction, with clarification that the equatorial radius is the one that contracts. The resulting volume ratio of the sphere to the oblate spheroid reflects this change, emphasizing the impact of relativistic effects on geometric shapes. Understanding these transformations is crucial for solving problems related to length contraction in special relativity.
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Homework Statement


Show that the length contraction deforms a sphere in motion to an oblate rotational ellipsoid whose volume decreases by a factor of γ (gamma)


Homework Equations


x=x'/γ v=4∏r^3/3 (volume for sphere) v=4∏(a^2)b/3 (volume for prolate and oblate spheroid)


The Attempt at a Solution


The question is taken from Special relativity for beginners by Jurgen Freund. Firstly, I am confused as to why the question claims that the sphere would deform into an oblate spheroid rather than a prolate spheroid since length contraction does not contract transversely. Anyway by length contraction, the radius (r) of the sphere would contract by a factor of γ, Therefore:
r=a/γ where a is the equatorial radius and b is the polar radius. By subbing r=a/γ into the formula of sphere, through some algebraic manipulation, I get a spheroid whose radius decreased by a factor of γ^3 instead. How should I go about doing it and where are my errors ?

Please help.

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So what happens to the sphere with the length contraction? The direction parallel to motion is contracted, and the two perpendicular to it are not, right? So which of a and b are transformed?
 
The equatorial radius (a) of the prolate spheroid would be contracted by a factor of γ. (i.e a=r/γ). Therefore the volume of the sphere is V=4∏(r^3)/3 and the volume of the prolate spheroid would be V'=4∏(r^2)b/3(γ^2). Finally, taking the volume of the sphere and divide it by the volume of the prolate spheroid gives (V/V')=r(γ^2)/b ??

Sorry if I am slow at catching ideas. Please bear with me.

Thank you very much
 
physikamateur said:
The equatorial radius (a) of the prolate spheroid would be contracted by a factor of γ. (i.e a=r/γ). Therefore the volume of the sphere is V=4∏(r^3)/3 and the volume of the prolate spheroid would be V'=4∏(r^2)b/3(γ^2). Finally, taking the volume of the sphere and divide it by the volume of the prolate spheroid gives (V/V')=r(γ^2)/b ??

Sorry if I am slow at catching ideas. Please bear with me.

Thank you very much

Watch out. It is b which is contracted whereas "a" remains equal to the initial radius.
 
physikamateur said:
The equatorial radius (a) of the prolate spheroid would be contracted by a factor of γ. (i.e a=r/γ).

Why?
 
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